Answer:
3
Explanation:
A cyclic event is one that happens repeatedly.
The appearance of Hailey's Comet is a cyclic event because it has happened in various occasions in the past on a regular schedule as predicted. We have every reason to believe that the appearance of Hailey's Comet every 75 years will continue to be happen until the comet ceases to exist.
Superscript o subscript negative 1 e.
Explanation:
The nuclear reactions is of 2 types, one is nuclear fusion and the other one is nuclear fission.
Nuclear fusion is nothing but the combining of 2 nuclei with an emission of energy along with an electron, proton or beta particle.
Nuclear fission is the break down of a nucleus into 2 or more nuclei along with an electron, proton or beta particle.
And the reaction is,
₅₆B¹²⁴ ₅₅C¹²⁴ + ₋₁e⁰
So the blank was filled by means of a beta particle.
<span>Calculating the moles and the moles ratio of the elements gives us the ratio of atoms in each element.
Converting the percentage of element into grams
40.25% carbon = 40.25/100 = .4025 * 100 g of carbon = 40.25g of C
6.19% hydrogen = 6.19/100 = .0619 * 100g g of hydrogen = 6.19g of H
8.94% oxygen = 8.94/100 = .0819 * 100 g of oxygen = 8.19g of O
44.62% bromine = 44.62/100 = .4462 * 100 g of bromine = 44.62g of Br
Converting the grams of element into moles
(48.38 g C) (1 mol/ 12.10 g C) = 4.028 mol C
(8.12 g H) (1 mol/ 1.008 g H) = 8.056 mol H
(53.38 g O) (1 mol/ 16.00 g O) = 3.336 mol O
(44.62g of Br)(0.012515018021626 moles) = 0.55842 mol Br
Calculating the moles ratio of elements by dividing the small number of moles of an element
4.028 mol C /0.55842 = 7.2 mol C x 5 = 36 mol C
8.056 mol H / 0.55842 = 14.42 mol H = 72 mol H
3.336 mol O / 0.55842 = 5.97 mol O = 30 mol O
0.55842 mol Br / 0.55842 = 1mol Br = 5 mol Br
So the empirical formula is (C6H12O5)6Br5</span>
A.) The conversion factor is 1 amu =

To know how many amu in

grams of neutrons:

=1.00811 amu
b.) The mass in grams of one lithium ion which has an atomic weight of 6.94 amu.

=

c.) How many amu in 6.492x10^-23g potassium?

= 39.0957 amu
Answer:
Each specific property of motif and domain is explained.
Explanation:
Domain;
- May retain a 3D structure when separated from rest of the protein.
- Unit of tertiary structure because alpha helix and beta sheets are units of secondary structure.
- Stable globular units like pyruvate kinase
- May be distinct functional units in a protein
Motif;
- Repetetive supersecondary structure because they contain cluster of secondary structure.
- Beta Alpha Beta unit is an example of motif
- Clusters of secondary structure
Both Motif and Domain;
- Stabilized by hydrophobic interactions like hydrogen bonding stabilize the both.
- Depends on primary structure like the arrangement of amino acid in polypeptide chain determine the secondary and tertiary structure of proteins.