When Holly injures her shoulder playing baseball, she uses an instant ice pack to reduce the swelling. She breaks the inner, act
1 answer:
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The question is missing the diagram. Also, the choices must have pictorial representation. So, I have attached the missing diagram and the pictorial representation of the vectors.
Answer:
The correct representation is attached below. Force and acceleration will be towards the center of rotation while the velocity will be along the tangent to the circular motion. <u>Option (D).</u>
Explanation:
From the figure, we can conclude the following points:
1. The cylinder is under a uniform circular motion as the circular table is moving at constant speed.
2. For a circular motion, velocity acts along the tangent to the circular path.
3. For a circular motion, centripetal force acts on the body that causes it move around a circular path.
4 The direction of the centripetal force is radially inward towards the center of rotation.
5. The centripetal force causes a centripetal acceleration acting on the body.
6. From Newton's second law, the net acceleration of a body is in the same direction as that of the net force acting on it. So, centripetal acceleration also acts in the radially inward direction.
Therefore, from the above conclusions, it is clear that velocity will act in the horizontal direction at the given instance of time and force and acceleration will act vertically down for the given instance.
This is shown in the picture below. The option (D).
Answer:
Explanation:
first write the newtons second law:
F=δma
Applying bernoulli,s equation as follows:
∑
Where, is the pressure change across the streamline and
is the fluid particle velocity
substitute for {tex]γ[/tex] and
for
integrating the above equation using limits 1 and 2.
there the bernoulli equation for this flow is
note: =density(ρ) in some parts and change(δ) in other parts of this equation. it just doesn't show up as that in formular
Answer:
F = - 59.375 N
Explanation:
GIVEN DATA:
Initial velocity = 11 m/s
final velocity = 1.5 m/s
let force be F
work done = mass* F = 4*F
we know that
Change in kinetic energy = work done
kinetic energy =
kinetic energy = = -237.5 kg m/s2
-237.5 = 4*F
F = - 59.375 N