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2 years ago

How do you find the molar mass for ba(NO3)2

1 answer:

8 0

To find the molar mass of Ba(NO3)2, determine the molar masses of all the atoms that form it. The Molar mass for Barium nitrate is 261.337 g/mol.

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At 700 K, Kp for the following equilibrium is (5.6 x 10-3) 2HgO(s)--> 2Hg(l) + O2(g) Suppose 51.2 g of mercury(II) oxide is p

Vesnalui [34]

Answer: Option (B) is the correct answer.

Explanation:

According to the given reaction equation, formula to calculate $\Delta n$ is as follows.

$\Delta n$ = coefficients of gaseous products - gaseous reactants

= 1 - 0

= 1

Also we know that,

$K_{p} = K_{c} \times (RT)^{\Delta n}$

$5.6 \times 10^{-3} = K_{c} \times (0.0821 \times 700)^{1}$

$K_{c} = 0.097 \times 10^{-3}$

For the equation, $2HgO(s) \rightarrow 2Hg(l) + O_{2}(g)$

Activity of solid and liquid = 1

As, $K_{p} = \frac{P^{2}_{Hg} \times P_{O_{2}}}{P^{2}_{HgO}}$

$5.6 \times 10^{-3} = P_{O_{2}}$

Hence, $P_{O_{2}}$ = 0.0056 atm

Thus, we can conclude that partial pressure of oxygen gas at equilibrium is 0.0056 atm.

5 0

2 years ago

If a person looking at a poster sees green instead of yellow and doesn't see red at all, this person most likely has color blind

Inga [223]

People with protanopia are unable to sense any ‘red’ light, people with deuteranopia do not sense ‘green’ light and people with tritanopia cannot sense ‘blue’ light. If a person perceives the color green, then the yellow sensitive nerves must work somewhat effectively since green is a combination of yellow and blue. Red-sensitive nerves are most likely not responding properly for this person. The answer is C.

5 0

2 years ago

Read 2 more answers

3. Scott and James work at a grocery store. After the grocery store closed, they were playing a game with a shopping cart and Sc

weqwewe [10]

Answer: B) Crash 2; the force on the cart was stronger in this crash, so the force on the skateboard was also stronger.

Explanation:

6 0

1 year ago

Perform the following conversion: 6.1 × 103 K (the surface temperature of the Sun) to °F and °C. Pay attention to the number of

Keith_Richards [23]

Answer:

$\°C=5.8x10^3\°C$

$\°F=1.1x10^4\°F$

Explanation:

Hello,

In this case, for the calculation of the temperature in degree Celsius we subtract 273.15 to the given temperature in kelvins:

$\°C=6100-273.15\\\\\°C=5.8x10^3\°C$

Next, by applying the following equation we compute it in degree Fahrenheit:

$\°F=(5.8x10^{3}*9/5) + 32\\\\\°F=1.1x10^4\°F$

Clearly, since the initial unit has two significant figures the computed units also show two significant figures.

Regards.

5 0

2 years ago

Suppose that 0.323 g of an unknown sulfate salt is dissolved in 50 mL of water. The solution is acidified with 6M HCl, heated, a

geniusboy [140]

Answer:

1) 41.16 % = 0.182 grams

2) The alkali cation is K+ , to form the salt K2SO4

Explanation:

Step 1: Data given

Mass of unknown sulfate salt = 0.323 grams

Volume of water = 50 mL

Molarity of HCl = 6M

Step 2: The balanced equation

SO4^2- + BaCl2 → BaSO4 + 2Cl-

Step 3: Calculate amount of SO4^2- in BaSO4

The precipitate will be BaSO4

The amount of SO4^2- in BaSO4 = (Molar mass of SO4^2-/Molar mass BaSO4)*100 %

The amount of SO4^2- in BaSO4 = (96.06 /233.38) * 100

= 41.16%

So in 0.443g of BaSO4 there will be 0.443 * 41.16 % = 0.182 grams

2. If it is assumed that the salt is an alkali sulfate determine the identity of the alkali cation.

The unknown sulphate salt has 0.182g of sulphate. This means the alkali cation has a weight of 0.323-0.182 = 0.141g grams

An alkali cation has a chargoe of +1; sulphate has a charge of -2

The formula will be X2SO4 (with X = the unknown alkali metal).

Calculate moles of sulphate

Moles sulphate = 0.182 grams (32.1 + 4*16)

Moles sulphate = 0.00189 moles

The moles of sulphate = 0.182/(32.1+16*4)

The moles of sulphate = 0.00189 moles

X2SO4 → 2X+ + SO4^2-

For 2 moles cation we have 1 mol anion

For 0.00189 moles anion, we have 2*0.00189 = 0.00378 moles cation

Calculate molar mass

Molar mass = mass / moles

Molar mass = 0.141 grams / 0.00378 grams

Molar mass = 37.3 g/mol

The closest alkali metal is potassium. (K2SO4 )

3 0

2 years ago