What is the net force required to give an automobile with a mass of 1,600 kg an acceleration of 4.5 m/s2

Two identical objects A and B fall from rest from different heights to the ground. If object B takes twice as long as A to reach

aivan3 [116]

I believe this ratio is 4:1 due to the inverse square law

4 0

2 years ago

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A 50.-kilogram rock rolls off the edge of a cliff. if it is traveling at a speed of 24.2 m/s when it hits the ground, what is th

ElenaW [278]

The correct answer to the question is : 29.88 m.

EXPLANATION :

As per the question, the mass of the rock m = 50 Kg.

The rock is rolling off the edges of the cliff.

The final velocity of the rock when it hits the ground v = 24 .2 m/s.

Let the height of the cliff is h.

The potential energy gained by the rock at the top of the cliff = mgh.

Here, g is known as acceleration due to gravity, and g = $9.8\ m/s^2$

When the rock rolls off the edge of the cliff, the potential energy is converted into kinetic energy.

When the rock hits the ground, whole of its potential energy is converted into its kinetic energy.

The kinetic energy of the rock when it touches the ground is given as -

Kinetic energy K.E = $\frac{1}{2}mv^2$ .

From above we know that -

Kinetic energy at the bottom of the cliff = potential energy at a height h

$\frac{1}{2}mv^2=\ mgh$

⇒ $v^2=\ 2gh$

⇒ $h=\ \frac{v^2}{2g}$

⇒ $h=\ \frac{(24.2)^2}{2\times 9.8}$

⇒ $h=\ 29.88\ m$

Hence, the height of the cliff is 29.88 m

5 0

2 years ago

Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 meters. Then Andrew kicks the ball straight

hram777 [196]

Answer:

22.7 meters

Explanation:

Let's remind the difference between distance and displacement:

- distance: the total distance travelled by an object in all its paths

- displacement: the different between the final and initial position of the object

In this case, the problem asks to find the distance covered by the ball. This will be the sum of the distances covered by the ball in each part of its motion, therefore:

$d=13.2 m+9.5 m=22.7 m$

(instead, the displacement will be the difference between the final and initial position of the ball, therefore:

$d=13.2 m-9.5 m=3.7 m$ )

4 0

2 years ago

You have been hired to check the technical correctness of an upcoming made-for-TV murder mystery that takes place in a space shu

AlladinOne [14]

Answer:

The astronaut who has a mass of 80 kg without the toolkit do survive with 40 seconds of remaining air

Explanation:

Due the astronaut throws the 10-kg tool kit away with a speed of 8 m/s, it gives a momentum equivalent but in the other direction, so $I=mv=(10Kg)(8m/s)=80kg*m/s$ , then we can find the speed that the astronaut reaches due to its weight we get, $v=\frac{I}{m} =\frac{80kg*m/s}{80Kg} =1m/s$ .

Finally, as the distance to the space shuttle is 200m, the time taken to the astronaut to reach it at the given speed will be $t=\frac{d}{v}=\frac{200m}{1m/s}=200s$ , as the remaining air time is 4 min or 240 seconds, The astronaut who has a mass of 80 kg without the toolkit do survive with 40 seconds of remaining air.