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Paul [167]
2 years ago
10

When Marcel finds the distance L from the previous part, it turns out to be greater than Lend, the distance from the pivot to th

e end of the seesaw. Hence, even with Jacques at the very end of the seesaw, the twins Gilles and Jean exert more torque than Jacques does. Marcel now elects to balance the seesaw by pushing sideways on an ornament (shown in red) that is at height h above the pivot. (Figure 3)With what force in the rightward direction, Fx, should Marcel push? If your expression would give a negative result (using actual values) that just means the force should be toward the left.Express your answer in terms of W, Lend, w, L2, L3, and h.
Physics
1 answer:
Llana [10]2 years ago
3 0

Answer:

Fx = - (1/h)( wL2 + wL3 - wLend )

Explanation:

Assuming The twins Gilles and Jean has a weight ( w ) each

The torque that would balance the equation would be = wL2 + wL3 -------- 1

THEREFORE the ccw torques are = wLend + Fh ----------- 2

hence equation 2 equals equation 1

= wLend + Fh = wL2 + wL3 --------- 3

equation 3 can as well be represented as

F = ( 1/h) ( wL2 + wL3 - wLend )---------- 4

From equation 4 it can be seen that F is on the left hand side therefore the value of Fx is negative

therefore equation 4 is represented as

 Fx = - (1/h)( wL2 + wL3 - wLend )

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A plane flying at 70.0 m/s suddenly stalls. If the acceleration during the stall is 9.8 m/s2 directly downward, the stall lasts
tino4ka555 [31]

Answer:

v = 66.4 m/s

Explanation:

As we know that plane is moving initially at speed of

v = 70 m/s

now we have

v_x = 70 cos25

v_x = 63.44 m/s

v_y = 70 sin25

v_y = 29.6 m/s

now in Y direction we can use kinematics

v_y = v_i + at

v_y = 29.6 - (9.81 \times 5)

v_y = -19.5 m/s

since there is no acceleration in x direction so here in x direction velocity remains the same

so we will have

v = \sqrt{v_x^2 + v_y^2}

v = \sqrt{63.44^2 + 19.5^2}

v = 66.4 m/s

4 0
2 years ago
Two long straight wires enter a room through a window. One carries a current of 2.9A into the room, while the other carries a cu
Degger [83]

Answer and Explanation:

curents i = 2.9 A

           i ' = 4.4 A

the magnitude (in T.m) of the path integral of B.dl around the window frame = μo * current enclosed

          = μo* ( i '- i )

Since from Ampere's law

where μ o = permeability of free space = 4π * 10 ^-7 H / m

plug the values we get the magnitude (in T.m) of the path integral of B.dl = ( 4π*10^-7 ) (2.9+4.4)

                                 = 1.884 * 10^-6 Tm

4 0
2 years ago
In the middle of the night you are standing a horizontal distance of 14.0 m from the high fence that surrounds the estate of you
olchik [2.2K]

PART A)

horizontal distance that will be moved = 14 m

Height of the fence = 5.0 m

height from which it is thrown = 1.60 m

angle of projection = 54 degree

So here we can say that stone will travel vertically up by distance

\Delta y = 5 - 1.6 = 3.40 m

now we will have displacement in horizontal direction

\Delta x = 14 m

now we know that

v_x = vcos54

v_y = vsin54

now we will have

\Delta x = v_x t

14 = (vcos54)t

also for y direction

\Delta y = v_y t + \frac{1}{2}at^2

3.40 = (vsin54)t - \frac{1}{2}(9.8) t^2

now from the two equations we will have

3.40 = (vsin54)(\frac{14}{vcos54}) - 4.9 t^2

3.40 = 14 tan54 - 4.9 t^2

3.40 = 19.3 - 4.9 t^2

t = 1.8 s

now from above equations

14 = vcos54 (1.8)

v = 13.2 m/s

So the minimum speed will be 13.2 m/s

Part B)

Total time of the motion after which it will land on the ground will be "t"

so its vertical displacement will be

\Delta y = -1.60 m

now we will have

-1.60 = v_y t + \frac{1}{2}at^2

-1.60 = (13.2sin54)t - \frac{1}{2}(9.8)t^2

4.9 t^2 - 10.7t - 1.60 = 0

t = 2.3 s

Now the time after which it will reach the fence will be t1 = 1.8 s

so total time after which it will fall on other side of fence

t_2 = t - t_1

t_2 = 2.3 - 1.8 = 0.5 s

now the displacement on the other side is given as

\Delta x = (vcos54) t_2

\Delta x = (13.2 cos54)(0.5)

\Delta x = 3.88 m

4 0
2 years ago
Question 1
Vesna [10]

Answer:

1)  g = 4π² / m, 3) xaxis the  length of the pendulums and the y axis the period squared

Explanation:

a) students can approximate this system to a simple pendulum, in this case the angular velocity is

         w = √ g / l

angular velocity, frequency and period are related

         w = 2π f = 2π / T

we substitute

         T = 2π√ l / g

with this equation they can determine the value of the acceleration of gravity, for this they measure the period for various lengths of the pendulum and graph

        T² = 4π²  l / g

We graph T² vs l

where this is the equation of a line if the independent variable is y = T² and x = l

        y = (4π² / g)  l

so the slope is

         m = 4π² / g

clearing

         g = 4π² / m

where the slope can be found with the values ​​of the line not the experimental values.

2) to carry out the experiment, or the thread is attached to the sphere, the length of the pendulum that goes from the pivot point to the center of the sphere is measured with a tape measure and a small finished angle is turned or less than 10th is released, it is good to wait for the first oscillation to walk, the time of a determined number of oscillations is generally measured 10 or 20, the period is calculated

    T = t / n

a table of T² against the length is made and it is plotted with the length in the ax ax, we look for the slope and hence the acceleration of gravity

3) on the independent x-axis, the controlled variable must be plotted, which is the length of the pendulums, and on the y-axis, the dependent variable is the period squared

4) of the equation of the line

            m = 4pi2 / g

                 where it ends up reaching the floor

            g = 4pi2 / m

5) when the spring is cut, the sphere remains under the effect of gravity acceleration, the harmonic movement disappears and the sphere is in a vertical movement

5 0
2 years ago
At the equator, the earth’s field is essentially horizontal; near the north pole, it is nearly vertical. In between, the angle v
Yanka [14]

Answer:

A current of 0.358A is required

Explanation:

Pls refer to attached document for more details

7 0
2 years ago
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