answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
allsm [11]
2 years ago
10

A lamp uses a 230 V mains supply and transfers 96 J of energy every second. Work out the current through the lamp. Give your ans

wer to 1 decimal place.
Physics
1 answer:
sertanlavr [38]2 years ago
8 0

Answer:

0.4 A

Explanation:

From the question,

Electric power = Voltage×current

P = VI.......................... Equation 1

Make I the subject of the equation

I = P/V..................... Equation 2

Given: P = 96 J/s, V = 230 V.

Substitute into equation 2

I = 96/230

I = 0.4 A.

Hence the current is 0.4 A

You might be interested in
Sara and Saba are identical twins who are the same in every way, including their weights. One day, Sara and Saba decided to go f
Sphinxa [80]

As Saba was wearing high heels they are long from the bottom so they sank however Sana was wearing snow boots which means they were flat and so she didn’t sink.

3 0
2 years ago
An inline skater skates on a circular track 120.0 m in diameter at a tangential speed of 9.20 m/s. If the skater’s mass is 68.5
jok3333 [9.3K]

Answer:

The centripetal force acting on the skater is <u>48.32 N.</u>

Explanation:

Given:

Radius of circular track is, R=120.0\ m

Tangential speed of the skater is, v=9.20\ m/s

Mass of the skater is, m=68.5\ kg

We are asked to find the centripetal force acting on the skater.

We know that, when an object is under circular motion, the force acting on the object is directly proportional to the mass and square of tangential speed and inversely proportional to the radius of the circular path. This force is called centripetal force.

Centripetal force acting on the skater is given as:

F_c=\frac{mv^2}{R}

Now, plug in the given values of the known quantities and solve for centripetal force, F_c. This gives,

F_c=\frac{68.5\times (9.20)^2}{120.0}\\\\F_c=\frac{68.5\times 84.64}{120}\\\\F_c=\frac{5797.84}{120}\\\\F_c=48.32\ N

Therefore, the centripetal force acting on the skater is 48.32 N.

3 0
2 years ago
Variations in the resistivity of blood can give valuable clues about changes in various properties of the blood. Suppose a medic
Elena-2011 [213]

Answer:

Answer:

1.1 x 10^9 ohm metre

Explanation:

diameter = 1.5 mm

length, l = 5 cm

Potential difference, V = 9 V

current, i = 230 micro Ampere = 230 x 10^-6 A

radius, r = diameter / 2 = 1.5 / 2 = 0.75 x 10^-3 m

Let the resistivity is ρ.

Area of crossection

A = πr² = 3.14 x 0.75 x 0.75 x 10^-6 = 1.766 x 10^-6 m^2

Use Ohm's law to find the value of resistance

V =  i x R

9 = 230 x 10^-6 x R

R = 39130.4 ohm

Use the formula for the resistance

R=\rho \frac{l}{A}

\rho =\frac{RA}{l}

\rho =\frac{39130.4\times 0.05}{1.766\times 10^{-6}}

ρ = 1.1 x 10^9 ohm metre

Explanation:

7 0
2 years ago
High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 43.7 m/s just before it strikes a 45
Helga [31]

Answer:

41.27m/s

Explanation:

According to law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the masses

u1 and u2 are the initial velocities

v is the velocity after impact

Given

m1 = 0.2kg

u1 = 43.7m/s

m2 = 45.9g = 0.0459kg

u2 = 30.7m/s

Required

Velocity after impact v

Substitute the given parameters into the formula

0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v

8.74+1.409 = 0.2459v

10.149 = 0.2459v

v = 10.149/0.2459

v = 41.27m/s

Hence the speed of the golf ball immediately after impact is 41.27m/s

8 0
2 years ago
A pulley 12 cm in diameter is free to rotate about a horizontal axle. A 220-g mass and a 470-g mass are tied to either end of a
Aleks [24]

Answer:0.147 N-m

Explanation:

Given

Diameter of Pulley d=12 cm

radius r=6 cm

mass of first object m_1=220 gm

mass of second object m_2=470 gm

Now both masses will exert a torque a on Pulley

Torque due to first Pulley T_1=m_1g\cdot r

T_1=0.22\times 9.8\times 0.06=0.129 N-m

Torque due to second mass on Pulley T_2=m_2g\cdot r

T_2=0.276 N-m

Total Torque by masses T_{net}=T_2-T_1

T_{net}=0.276-0.129=0.147 N-m

so we need to apply a torque of magnitude 0.147 N-m opposite to the direction of T_{net}  

3 0
2 years ago
Other questions:
  • What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in m
    7·2 answers
  • A 125g steel ball with a kinetic energy of .25j rolls along a horizontal track how high up an inclined track will the ball roll
    5·1 answer
  • A baseball bat is 32 inches (81.3 cm) long and has a mass of 0.96 kg. Its center of mass is 22 inches (55.9 cm) from the handle
    11·1 answer
  • A ball of mass 5.0kg is lifted off the floor a distance of 1.7m. 1. What is the change in the gravitational potential energy of
    13·1 answer
  • The furnace keeps houseAat 25◦C, while thefurnace in houseBkeeps it at 20◦C. Which house requires heat to be supplied by its fur
    7·1 answer
  • Gamma rays may be used to kill pathogens in ground beef. One irradiation facility uses a 60Co source that has an activity of 1.0
    6·1 answer
  • A small glass bead charged to 5.0 nCnC is in the plane that bisects a thin, uniformly charged, 10-cmcm-long glass rod and is 4.0
    10·1 answer
  • Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
    12·1 answer
  • It took a squirrel 0.50\,\text s0.50s0, point, 50, start text, s, end text to run 5.0\,\text m5.0m5, point, 0, start text, m, en
    15·2 answers
  • 1. The gravitational pull of the sun on Earth keeps Earth orbiting around the sun. Which statement is correct about the force th
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!