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WINSTONCH [101]
2 years ago
4

After passing through pyruvate dehydrogenase and the citric acid cycle, one mole of pyruvate will result in the formation of ___

_____ moles of carbon dioxide and ________ mole(s) of ATP (or GTP).A) 2; 2B) 2; 1C) 3; 2D) 3; 1
Chemistry
1 answer:
faltersainse [42]2 years ago
8 0

Answer:

C

Explanation:

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In redox half-reactions, a more positive standard reduction potential means I. the oxidized form has a higher affinity for elect
qwelly [4]

Answer:

The 1st and 4th options are correct

I.the oxidized form has a higher affinity for electrons

IV. the greater the tendency for the oxidized form to accept electrons

Explanation:

Half reaction can be described as the oxidation or reduction reaction in a redox reaction.it is In the redox rection there is a change in the oxidation states of Chemical species involved. the oxidized form in the redox has a higher affinity for electrons and the greater the tendency for the oxidized form to accept electrons.

Standard reduction potential which is also referred to as standard cell potential can be described as the potential difference that exist between cathode and anode of the cell. In the standard reduction potential most times the species will be reduced which is usually analysed in a reduction half reaction.

(Standard Hydrogen Electrode) is utilized when determining the Standard reduction or potentials of a chemical specie. this is because of Hydrogen having zero reduction and oxidation potentials, as a result of this a measured potential of any species is compared with that of Hydrogen, the difference helps to know the potential reduction of that particular specie.

4 0
2 years ago
A 360mg sample of aspirin, C9H8O4, (molar mass 180g), is dissolved in enough water to produce 200mL of solution. What is the mol
notsponge [240]

Answer:

Molarity is 0.04M

Explanation:

First of all, let's determinate the moles of aspirin in that sample

Mass / Molar mass = Moles

360 mg = 0.360 g

0.360 g / 180 g/m = 0.002 moles

This moles that are included in 200 mL of solution, are also in 50 mL.

So molarity is mol/L

50 mL = 0.05 L

0.002 m / 0.05 L = 0.04M

6 0
2 years ago
Calculate δg o for each reaction using δg of values:(a) h2(g) + i2(s) → 2hi(g) kj (b) mno2(s) + 2co(g) → mn(s) + 2co2(g) kj (c)
steposvetlana [31]
Part (a) :
H₂(g) + I₂(s) → 2 HI(g)
From given table:
G HI = + 1.3 kJ/mol
G H₂ = 0
G I₂ = 0
ΔG = G(products) - G(reactants) = 2 (1.3) = 2.6 kJ/mol

Part (b):
MnO₂(s) + 2 CO(g) → Mn(s) + 2 CO₂(g)
G MnO₂ = - 465.2
G CO = -137.16
G CO₂ = - 394.39
G Mn = 0
ΔG = G(products) - G(reactants) = (1(0) + 2*-394.39) - (-465.2 + 2*-137.16) = - 49.3 kJ/mol

Part (c):
NH₄Cl(s) → NH₃(g) + HCl(g)
ΔG = ΔH - T ΔS
ΔG = (H(products) - H(reactants)) - 298 * (S(products) - S(reactants))
      = (-92.31 - 45.94) - (-314.4) - (298 k) * (192.3 + 186.8 - 94.6) J/K
      = 176.15 kJ - 84.78 kJ = 91.38 kJ 
 





 
6 0
2 years ago
Read 2 more answers
Consider the following properties: I) The red color of rubies is due to the presence of chromium ions. II) Objects made of silve
Alenkinab [10]

Answer:

Only II) is correct

Explanation:

I) The red color of the rubies is a physical property of its own structure (wich contains  chromium ions)

II)Objects made of silver become tarnished not by a physical property, but as the result of a chemical reaction on the surface of the object made of silver in combination with the sulfur in the air

2Ag_{(s)}+S\rightarrow Ag_{2}S

This changes the color of the object to black, (similar to the iron oxidation)

iii)Boiling is a physical change where a liquid substance absorbs heat in some way (e.g. a flame) and becomes a gas

6 0
2 years ago
The solubility of glucose at 30°C is 125 g/100 g water. Classify a solution made by adding 550 g of glucose to 400 mL of water a
seraphim [82]
The simplified solubility of glucose at 30°C is 1.25 g/g of water. Considering that the density of water at 30°C is 1 g/mL, the equivalent mass of 400 mL of water is also 400g. 

The concentration of the solution in water is,
                            550 g/400g of water = 1.375 g glucose / g of water

Since the concentration is higher compared to the solubility of glucose at the specified temperature, it can be said that the solution is SATURATED.
4 0
2 years ago
Read 2 more answers
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