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skad [1K]
2 years ago
8

A charge Q is placed at the center of an inflated latex balloon of radius R. If, you let half the air out of the balloon to let

it contract uniformly, the electric flux through the balloon would:
Physics
1 answer:
lilavasa [31]2 years ago
3 0

Answer:

<em>The electric flux through the balloon remains unchanged.</em>

Explanation:

Letting half of the air out of the balloon will reduce the area of the balloon by 4 times its initial area. Also, since the area is reduced, then, the field lines passing through the balloon will then become closer, or technically increase by four times. The general effect is that there will be no change in the electric flux through the balloon due to the reduced radius.

Mathematically,

Ф = AE

where A is the area of the balloon

E is the electric field around the balloon

Ф is the electric flux around the balloon

If the radius is halved, then the area of the balloon is reduced by four times from A to A/4.

The field through the balloon also increase from E to 4E

The resulting electric flux due to these changes will be

Ф = A/4 * 4E = AE

Technically, the flux does not change.

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A girl is shown at position A on a swing when the seat is directly below the support bar. The seat is then at height A as shown
MrRa [10]

Answer:

<u></u>

  • <u>1. The potential energy of the swing is the greatest at the position B.</u>

  • <u>2. As the swing moves from point B to point A, the kinetic energy is increasing.</u>

Explanation:

Even though the syntax of the text is not completely clear, likely because it accompanies a drawing that is not included, it results clear that the posittion A is where the seat is at the lowest position, and the position B is upper.

The gravitational <em>potential energy </em>is directly proportional to the height of the objects with respect to some reference altitude. Thus, when the seat is at the position A the swing has the smallest potential energy and when the seat is at the <em>position B the swing has the greatest potential energy.</em>

Regarding the forms of energy, as the swing moves from point B to point A, it is going downward, gaining kinetic energy (speed) at the expense of the potential energy (losing altitude). When the seat passes by the position A, the kinetic energy is maximum and the potential energy is miminum. Then the seat starts to gain altitude again, losing the kinetic energy and gaining potential energy, up to it gets to the other end,

7 0
2 years ago
Read 2 more answers
The average mass of an automobile in the United States is about 1.440x10^6 g express this mass in kilograms
-BARSIC- [3]
From the problem statement, this is a conversion problem. We are asked to convert from units of grams to units of kilograms. To do this, we need a conversion factor which would relate the different units involved. We either multiply or divide this certain value to the original measurement depending on what is asked. From literature, we will find that 1000 grams is equal to 1 kilogram. We use this as follows:

<span> 1.440x10^6 g ( 1 kg / 1000 g ) = 1440 kg</span><span>
</span>
8 0
2 years ago
According to a rule-of-thumb. every five seconds between a lightning flash and the following thunder gives the distance to the f
Bond [772]

Answer:

S_{s}=300 m/s

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

Explanation:

In order to use the rule of thumb to find the speed of sound in meters per second, we need to use some conversion ratios. We know there is 1 mile per every 5 seconds after the lightning is seen. We also know that there are 5280ft in 1 mile and we also know that there are 0.3048m in 1ft. This is enough information to solve this problem. We set our conversion ratios like this:

\frac{1mi}{5s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}=321.87m/s

notice how the ratios were written in such a way that the units got cancelled when calculating them. Notice that in one ratio the miles were on the numerator of the fraction while on the other they were on the denominator, which allows us to cancel them. The same happened with the feet.

The problem asks us to express the answer to one significant figure so the speed of sound rounds to 300m/s.

For the second part of the problem we need to use conversions again. This time we will write our ratios backwards and take into account that there are 1000m to 1 km, so we get:

\frac{5s}{1mi}*\frac{1mi}{5280ft}*\frac{1ft}{0.3048m}*\frac{1000m}{1km}=3.11s/km

This means that for every 3.11s there will be a distance of 1km from the place where the lightning stroke. Since this is a rule of thumb, we round to the nearest integer for the calculations to be made easily, so the rule goes like this:

The rule for kilometers is that every three seconds between a lightning flash and the following thunder gives the distance to the flash in kilometers.

3 0
2 years ago
Your 64-cm-diameter car tire is rotating at 3.5 rev/s when suddenly you press down hard on the accelerator. After traveling 200
andreyandreev [35.5K]

Answer: angular acceleration = 0.748rad/s²

Explanation: according to the question, our answer needs to be in rad/s², thus all units in rev/s will be converted to rad/s

Assuming the motion of the object is of a constant angular acceleration, then newton's laws of motion is applicable.

The formulae below is used

v² = u² + 2αθ

v = final angular speed =6rev/s = 6*2π = 12π rad/s

u =initial angular speed =3.5rev/s = 3.5 *2π = 7π rad/s

Note 1 rev = 2π rad.

α = angular acceleration.

θ = angular displacement.

Diameter = 64cm = 0.64m, radius = 64/2 = 32cm = 0.32m

The angular displacement can be gotten using the formulae below

S = rθ, where s= linear distance covered = 200m, r = radius = 0.32m

θ = S/r = 200/0.32=625 rad.

By substituting the parameter we have that

(12π)² = (7π)² + 2α(625)

1421.22 = 486.31 + 1250α

1421.22 - 486.31 = 1250α

934.91 = 1250α

α = 934.91/1250

α= 0.748 rad/s²

4 0
2 years ago
an NHL hockey player (m=90 kg) stands motionless on the ice . the 10 kg stanley cup is thrown to the player at 4m/s. after he ca
spayn [35]

Answer:v=0.4 m/s

Explanation:

Mass hockey player m_1=90 kg

mass of  cup m_2=10 kg

Velocity of cup u=4 m/s

let v be the velocity of the combined system

Conserving momentum

m_1\cdot 0+m_2u=(m_1+m_2)v

v=\frac{10\times 4}{100}

v=\frac{40}{100}

v=0.4 m/s

4 0
2 years ago
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