Question

A string is 3.00 m long with a mass of 5.00 g. The string is held taut with a tension of 500.00 N applied to the string. A pulse is sent down the string. How long does it take the pulse to travel the 3.00 m of the string

Answer 1

Answer:

The time interval is $t = 5.48 *10^{-3} \ s$

Explanation:

From the question we are told that

   The length of the string is  $l = 3.00 \ m$

    The  mass of the string is $m = 5.00 \ g = 5.0 *10^{-3}\ kg$

     The  tension on the string is  $T = 500 \ N$

   

The  velocity of the pulse is mathematically represented as

      $v = \sqrt{ \frac{T}{\mu } }$

Where $\mu$ is the linear density which is mathematically evaluated as

       $\mu = \frac{m}{l}$

substituting values

     $\mu = \frac{5.0 *10^{-3}}{3}$

     $\mu = 1.67 *10^{-3} \ kg /m$

Thus  

     $v = \sqrt{\frac{500}{1.67 *10^{-3}} }$

    $v = 547.7 m/s$

The time taken is evaluated as

    $t = \frac{d}{v}$

substituting values

      $t = \frac{3}{547.7}$

      $t = 5.48 *10^{-3} \ s$