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Lina20 [59]
2 years ago
11

ocho libros cada uno de 4.0cm de espesor y masa de 1.8 kg, se encuentra en posición horizontal sobre una mesa ¿ cuanto trabajo s

e requiere para apilarlos uno sobre otro?
Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

El trabajo requerido es 1.978 julios

Explanation:

La cantidad de trabajo para apilar cada libro = Masa del libro, m × Aceleración debido a la gravedad, g × Altura del libro, h

La altura de cada libro = 4.0 cm. = 0.004 m

El primer libro es la primera capa, otros libros se colocan encima

Altura del primer libro levantado = 0

El trabajo realizado en el primer libro = 1.8 × 9.81 × 0 = 0

Trabajo realizado para el segundo libro = 1.8 * 9.81 * 0.004 = 0.071 J

Trabajo realizado para el tercer libro = 1.8 * 9.81 * 0.004 * 2 = 0.141 J

Trabajo realizado para el cuarto libro = 1.8 * 9.81 * 0.004 * 3 = 0.212 J

Trabajo realizado para el quinto libro = 1.8 * 9.81 * 0.004 * 4 = 0.283 J

Trabajo realizado para el sexto libro = 1.8 * 9.81 * 0.004 * 5 = 0.353 J

Trabajo realizado para el séptimo libro = 1.8 * 9.81 * 0.004 * 6 = 0.424 J

Trabajo realizado para el octavo libro = 1.8 * 9.81 * 0.004 * 7 = 0.494 J

El trabajo total realizado = 0.071 + 0.141 + 0.212 + 0.283 +0.353 + 0.424 + 0.494 = 1.978 J.

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Seema knows the mass of basketball. What other information is needed to find the balls potential energy
Lelu [443]

Answer: The height (position) of the ball and the acceleration due gravity

Explanation:

In this case we are taking about gravitational potential energy, which is the energy a body or object possesses, due to its position in a gravitational field.  In this sense, this energy depends on the relative height of an object with respect to some point of reference and associated with the gravitational force.  

In the case of the Earth, in which the gravitational field is considered constant, the gravitational potential energy U will be:  

U=mgh  

Where:

m is the mass of the ball

g=9.8 m/s^{2} is the acceleration due gravity (assuming the ball is on the Earth surface)

h is the height (position) of the ball respect to a given point

Note the value of the gravitational potential energy is directly proportional to the height.

8 0
2 years ago
Read 2 more answers
1) What is the highest atomic number element a red dwarf star can produce in its core? a. Carbon b. Oxygen c. Helium d. Iron
bonufazy [111]

Answer:

1) c. Helium

2) Iron

3) False.

Explanation:

1. Red dwarf is the smallest and the coolest star on the sequence. These are common stars in the milky way. Red dwarfs contains metals and the elements with higher atomic number. It is found that Helium is produced in red dwarf stars.

2. Iron is the highest atomic number element that is produced in cores of largest stars. The highest mass stars can make all elements up to iron, which is the heaviest element they can produce.

3. The end of stars life is dependent on the mass they are born with. It is not necessary that all red dwarf stars will become white dwarf stars faster than sun like star.

3 0
2 years ago
A child blows a leaf straight up in the air from rest. The leaf accelerates at 1.0\,\dfrac{\text m}{\text s^2}1.0 s 2 m1, point,
Neko [114]

Answer:

Time taken by the leaf to displace by 1.0 m distance is

t = \sqrt2 seconds

Explanation:

As we know that initial velocity of the leaf is given as

v_i = 0

now the acceleration upwards for the leaf is

a = 1 m/s^2

The displacement of leaf in upward direction is

d = 1 m

so now we have

d = v_i t + \frac{1}{2}at^2

1 = 0 + \frac{1}{2}(1) t^2

t = \sqrt2 seconds

3 0
2 years ago
Read 2 more answers
In a circus act, an acrobat rebounds upward from the surface of a trampoline at the exact moment that another acrobat, perched 9
slega [8]

Answer:

1.6 secs

Explanation:

In a circus act, an acrobat upwards from the surface of a trampoline

At that same moment another acrobat perched 9.0m above him

A ball is released from rest

While still in motion the acrobat catches the ball

He left the ball with a trampoline of 5.6m/s

Since the ball is falling downwards from a distance then acceleration will be negative

a= -9.8

s= d

s= 1/2at^2

= 1/2 × (-9.8)t^2

= 0.5× (-9.8)t^2

d = -4.9t^2

Therefore the time the acrobat stays in the air before catching the ball can be calculated as follows

9 - 4.9t^2= 5.6t + 1/2(-9.8)t^2

9 - 4.9t^2= 5.6t + (-4.9)t^2

9 - 4.9t^2= 5.6t - 4.9t^2

9= 5.6t

t= 9/5.6

t= 1.6 secs

6 0
2 years ago
Because the soles of your shoes have cleats, you can exert a forward force of 100 N even on slippery ice. A 10-kg picnic cooler
Brilliant_brown [7]

Answer:

you must throw 3 snowballs

Explanation:

We can solve this exercise using the concepts of conservation of the moment, let's define the system as formed by the refrigerator and all the snowballs. Let's write the moment

Initial. Before bumping that refrigerator

          p₀ = n m v₀

Where n is the snowball number

Final. When the refrigerator moves

         pf = (n m + M) v

The moment is preserved because the forces during the crash are internal

        n m v₀ = (n m + M) v

        n m (v₀ - v) = M v

        n = M/m    v/(vo-v)

Let's look for the initial velocity of the balls, suppose the person throws them with the maximum force if it slides in the snow (F = 100N), let's use the second law and Newton

          F = m a

          a = F / m

The distance the ball travels from zero speed to maximum speed is the extension of the arm (x = 1 m), let's look kinematically for the speed of the balls when leaving the arm

          v₁² = v₀² + 2 a x

          v₁² = 0+ 2 (100/1) 1

          v₁ = 14.14 m / s

This is the initial speed for the crash

         v₀ = v = 14.14 m / s

  Let's calculate

           n = M/m   v/ (v₀-v)

           n = 10/1   3 / (14.14 -3)

          n = 2.7 balls

you must throw 3 snowballs

7 0
2 years ago
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