Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where 
=Angular frequency
A=Amplitude
Using the formula
Hence, the amplitude of oscillation=A=0.199
Answer:
C = 3.77*10⁻¹⁰ F = 377 pF
Q = 1.13*10⁻⁵ C
Explanation:
Given
D = 8.0 cm = 0.08 m
d = 0.95 cm = 0.95*10⁻² m
k = 80.4 (dielectric constant of the milk)
V = 30000 V
C = ?
Q = ?
We can get the capacitance of the system applying the formula
C = k*ε₀*A / d
where
ε₀ = 8.854*10⁻¹² F/m
and A = π*D²/4 = π*(0.08 m)²/4
⇒ A = 0.00502655 m²
then
C = (80.4)*(8.854*10⁻¹² F/m)*(0.00502655 m²) / (0.95*10⁻² m)
⇒ C = 3.77*10⁻¹⁰ F = 377 pF
Now, we use the following equation in order to obtain the charge on each plate when they are fully charged
Q = C*V
⇒ Q = (3.77*10⁻¹⁰ F)*(30000 V)
⇒ Q = 1.13*10⁻⁵ C
Answer:
Kindly check explanation
Explanation:
Length of race = 5km
Maximum speed = 45 yards
Converting from yards to kilometer :
1km = 1093.613 yards
x = 45 yards
(1093.613 * x) = 45
x = 45 / 1093.613
x = 0.0411480 km
Where x = maximum length for which he can maintain his maximum speed expressed in kilometers.
Therefore, with the available information, it can be concluded that Lamar cannot maintain his maximum speed for the entire 5km race and will only be able maintain his maximum speed for 0.0411 kilometers.
Refer to the diagram shown below.
Because the ramp is slippery, ignore dynamic friction.
Let m = the mass of the frog.
g = 9.8 m/s²
The KE (kinetic energy) at the bottom of the ramp is
KE₁ = (1/2)*(m kg)*(5 m/s)² = 12.5 m J
Let v = the velocity at the top of the ramp.
The KE at the top of the ramp is
KE₂ = (1/2)*m*v²= 0.5 mv² J
The PE (potential energy) at the top of the ramp relative to the bottom is
PE₂ = (m kg)*(9.8 m/s²)*(1 m) = 9.8m J
Conservation of energy requires that
KE₁ = KE₂ + PE₂
12.5m = 0.5mv² + 9.8m
0.5v² = 2.7
v = 2.324 m/s
Answer: 2.324 m/s
