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Semenov [28]
2 years ago
10

What is the time spent by the alpha particle in the magnetic field?

Physics
1 answer:
Ber [7]2 years ago
7 0

the alpha-particle goes around a quarter of the circle, so the time it takes would be t=0.25×2.61×10−6s=6.5×10−7s.

I hope this help
You might be interested in
Lamar writes several equations trying to better understand potential energy. H = d with an arrow to the equation W = F d and P E
Debora [2.8K]

Answer:

The gravitational potential energy equals the work needed to lift the object.

Explanation:

here we know that

H = \vec d

work done is given as

W = \vec F . \vec d

Potential energy is given as

PE_g = mgh

force due to gravity is given as

\vec F_g = mg

now here if we plug in the value of distance and force in the formula of work done then we will have

W = (mg)(h)

so here we got

W = PE_g

so we can concluded that

The gravitational potential energy equals the work needed to lift the object.

3 0
2 years ago
Read 2 more answers
When the boy crashes his bumper car into the girl's bumper car, the momentum from his car is transferred to hers. What evidence
Darya [45]

Answer:

Where is the text?

Explanation:

If you refer to the short sentence you wrote as text, I believe the answer is probably the word "crashes" because it shows how the momentum was transferred.

8 0
2 years ago
Read 2 more answers
A race car has a maximum speed of 0.104 km/s .What is this speed in miles per hour ?
sweet [91]

Answer:

232.641374 mph

Explanation:

A race car has a maximum speed of 0.104km/s

Let X represent the speed in miles per hour

Therefore the speed in miles per hour can be calculated as follows

1 km/s = 2,236.936292 mph

0.104km/s = X

X = 0.104 × 2,236.936292

X = 232.641374

Hence the speed in miles per hour is 232.641374 mph

8 0
2 years ago
An object moving on the x axis with a constant acceleration increases its x coordinate by 82.9 m in a time of 2.51 s and has a v
Aneli [31]

We are given: Final velocity (v_f)=20 m/s .

Time t= 2.51 s and

distance s = 82.9 m.

We know, equation of motion

v_f = v_i + at.

Let us plug values of final velocity, and time in above equation.

20=v_i+a(2.51)

20=v_i+2.51a

Subtracting 2.51a from both sides, we get

20-2.51a=v_i  -----------equation(1)

Using another equation of motion

v_f-v_i=2as

Plugging values of vi =20-2.51a, t=2.51 and distnace s=82.9 in this equation.

We get,

20-(20-2.51a)=2*a(82.90)

Now, we need to solve it for a.

20-20+2.51a=165.8a.

-163.29a=0

a=0.

So, the acceleration would be 0 m/s^2.


5 0
2 years ago
If the angle of elevation of the cannon is decreased from 35 to 30 degrees, the vertical component of the ball's initial velocit
stealth61 [152]

Answer:

Determine the initial horizontal and vertical velocity for a dart launched with a ... an angle of 30 degrees. Vi=4m/s Vix Vicoso Mas cos 30 = = 30°. Viy=visine ... What is the resultant direction (angle) of the cannon ball (relative to a fixed frame)? ... Which of the following launch angles would result in the greatest time of flight iſ the.

Explanation:

I hope it helped

4 0
1 year ago
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