The more numbers after the decimal point there are, the more precise the instrument which recorded it is. For example, if one instrument during seismic activity records that the magnitude of the earthquake was 2.3, and another instrument recorded that it was 2.3645, the second instrument would have shown to be more precise.
Answer:
Molar concentration of the Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.
Explanation:
When you make a calibration curve in a spectrophotographic analysis you are applying the Lambert-Beer law that states the concentration of a compound is directely proportional to its absorbance:
A = E*l*C
<em>Where A is absorbance, E is molar absorption coefficient, l is optical path length and C is molar concentration</em>
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Using the equation of the line you obtain:
y = 4541.6X + 0.0461
<em>Where Y is absorbance and X is concentration -We will assume concentration is given in molarity-</em>
As absorbance of the unknown is 0.410:
0.410 = 4541.6X + 0.0461
X = 8.01x10⁻⁵M
<h3>Molar concentration of the Fe³⁺ in the unknown solution is 8.01x10⁻⁵M.</h3>
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<span>The statement that most accurately and effectively described the polarity and electronegativity in water is that the covalent bonds within these water molecules bind with the single oxygen atom in the molecule, as well as the two hydrogen atoms that it holds as well.</span>
A. N₂ (g) + 3 H₂ (g) --> 2 NH₃ (g)
B. The value for standard enthalpy of formation is empirical given that the reactants involved were pure elements. So, you can search this on the internet or in any textbook. The Hf for NH₃ is -46.0 kJ/mol.
C. C (s) + O₂ (g) --> CO₂ (g)
D. The Hf for CO₂ is <span>-393.5 kJ/mol
E. 4 Fe (s) + 3 O</span>₂ (g) --> 2 Fe₂O₃ (s)
F. The Hf for solid Fe₂O₃ is -826.0 kJ/mol.
G. C (s) + 2 H₂ (g) --> CH₄ (g)
H. The Hf for methane gas is -74.9 kJ/mol.
Answer:
1. When you see the moon, think of the whereabouts of the sun
2. The moon rises in the east and sets in the west, each and every day
3. The moon takes about a month (one month) to orbit the Earth
4. The moon’s orbital motion is toward the east
Explanation: