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Tanya [424]
2 years ago
7

Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf

ur with 5.99 g of oxygen, and compound B results from combining 8.60 g of sulfur with 12.88 g of oxygen. Show that the mass ratios in the two compounds are simple multiples of each other.
Chemistry
1 answer:
sukhopar [10]2 years ago
4 0

Answer:

1.5

Explanation:

Given that :

Compound A and B are formed from Sulfur + Oxygen.

Compound A :

6g sulfur + 5.99g Oxygen

Compound B:

8.6g sulfur + 12.88g oxygen

Comparing the ratios :

Compound A:

S : O = 6.00 : 5.99

S/0 = 6.0g S / 5.99g O

Compound B :

S : O = 8.60 : 12.88

S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

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What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?
Maru [420]

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

<u>Step 1 :</u> Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

This means there is 0.05 mol per 100mL

e

<u>Step 2 </u>: calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

3 0
2 years ago
Read 2 more answers
An oxygen atom has a mass of and a glass of water has a mass of . Use this information to answer the question below. Be sure you
MariettaO [177]

Answer:

Number of moles of oxygen atoms having equal mass as  glass of water = 3.12 moles

<em>Note: The given question is missing some figures. Here is a complete similar question below.</em>

<em>An oxygen atom has a mass of 2.66*10^-23 g and a glass of water has a mass of 0.050 kg. What is the mass of 1 mole of oxygen atoms? Round your answer to 3 significant digits. How many moles of oxygen atoms have a mass equal to the mass of a glass of water? Round your answer to 2 significant digits.</em>

Explanation:

A mole of a substance contains the Avogadro number of particles = 6.02 * 10²³

Therefore a mole of oxygen atoms contains 6.02*10²³ atoms.

mass of 1 atom of oxygen = 2.66*10⁻²³ g

Mass of 1 mole of oxygen atoms = mass of 1 atom * number of atoms in 1 mole

Mass of 1 mole of oxygen atoms = 2.66*10⁻²³ g * 6.02*10²³  = 16. 01 g

Mass of a glass of water = 0.050 Kg or 50 g

To determine the number of moles of oxygen atoms that have a mass equal to a glass of water i.e. 50 g, the formula below is used;

<em>number of moles = mass/molar mass</em>

mass of oxygen atoms= 50 g, molar mass or mass of one mole of oxygen atoms = 16.01 g

Therefore, number of moles of oxygen atoms = 50 g / 16.01 g = 3.12 moles

4 0
2 years ago
Rank the boiling points of the following molecules from highest to lowest. butanone diethyl ether butane and butanol.
Gekata [30.6K]

Answer:

From highest to lowest:

butanol: 117.7 degree Celsius

butanone: 79.64 degree Celsius

diethyl ether: 34.6 degree Celsius

n-butane: -0.4 degree Celsius

7 0
2 years ago
What is the oxidation state of selenium in SeO3?​
ra1l [238]

Answer: The oxidation state of selenium in SeO3 is +6

Explanation:

SeO3 is the chemical formula for selenium trioxide.

- The oxidation state of SeO3 = 0 (since it is stable and with no charge)

- the oxidation number of oxygen (O) IN SeO3 is -2

- the oxidation state of selenium in SeO3 = Z (let unknown value be Z)

Hence, SeO3 = 0

Z + (-2 x 3) = 0

Z + (-6) = 0

Z - 6 = 0

Z = 0 + 6

Z = +6

Thus, the oxidation state of selenium in SeO3 is +6

8 0
2 years ago
One hour of bicycle riding can require 500-900 kcal of energy, depending on the speed, the terrain, and the weight of the racer.
solniwko [45]

Answer:

145 hours

Explanation:

Since one hour of riding a bicycle takes up 505 kcal of energy. It is also stated that one gram of body fat is equal to 7.70 kcal. Also, it is given that 1 pound of body fat is equal to 454 g.

Hence;

1 Ib= 454 g

21 Ib= 21 × 454/1 = 9534 g

But

1g of body fat = 7.70kcal

9534 g of body fat = 9534 × 7.70 kcal/1 = 73411.8 kcal

If 505 kcal is lost in 1 hour

73411.8 kcal is lost in 73411.8 kcal × 1hour/505k cal = 145 hours

3 0
2 years ago
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