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fgiga [73]
2 years ago
5

Rank the boiling points of the following molecules from highest to lowest. butanone diethyl ether butane and butanol.

Chemistry
1 answer:
Gekata [30.6K]2 years ago
7 0

Answer:

From highest to lowest:

butanol: 117.7 degree Celsius

butanone: 79.64 degree Celsius

diethyl ether: 34.6 degree Celsius

n-butane: -0.4 degree Celsius

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Devon’s laboratory is out of material to make phosphate buffer. He is considering using sulfate to make a buffer instead. The pk
sesenic [268]

Answer:

Is not possible to make a buffer near of 7.

Optimal pH for sulfate‑based buffers is 2.

Explanation:

The dissociations of H₂SO₄ are:

H₂SO₄ ⇄ H⁺ + HSO₄⁻ pka₁ = -10

HSO₄⁻ ⇄ H⁺ + SO₄²⁻ pka₂ = 2.

The buffering capacity is pka±1. That means that for H₂SO₄ the buffering capacity is in pH's between <em>-11 and -9 and between 1 and 3</em>, having in mind that pH's<0 are not useful. For that reason, <em>is not possible to make a buffer near of 7.</em>

The optimal pH for sulfate‑based buffers is when pka=pH, that means that optimal pH is <em>2.</em>

<em />

I hope it helps!

4 0
2 years ago
At STP, the element oxygen can exist as either O2 or O3 gas molecules. These two forms of the element have(1) the same chemical
zhuklara [117]
O2 and O3 are allotropes of Oxygen, therefore they have (4) different chemical and physical properties.
5 0
2 years ago
Read 2 more answers
Compute the end-to-end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule with a number-
MArishka [77]

Answer:

5156  Â

Explanation:

Chains of monomers that are being linked together constitute what is called polymers. in this question; we are to compute the end to end separation (direct distance between molecule ends), in Angstroms, of a coiled PVC molecule.

Using the following approach:

The first step is to determine the repeating units in polymer

The number of repeating unit = average molecular weight/  atomic weight of PVC

Given that:

average molecular weight = 256,131 g/mol

atomic weight of PVC = 62.498 g

Then;

The number of repeating unit = 256,131 g/mol /  62.498 g = 4098.227143 mol

Now the distance is calculated by using the formula:

d = (C-C) × sin 109.5/2

C-C bond length = 1.54 angstroms

tetrahedral bond angle = 109.5°

Then d = (1.54)  × sin 109.5/2

d = 1.258

Thus ; the end to end separation  is :

4098.227143  × 1.258 = 5155.57 Â

The answer is 5156  Â (since no decimal should be included )

6 0
2 years ago
2.A solid block with a length of 6.0 cm, a width of 3.0 cm, and a height of 3.0 cm has a mass of 146 g. What is the block’s dens
posledela
2: <span>Volume V = a*b*c = 6.0*3.0*3.0 = 54.0 cm^3                                                   density ρ = mass/volume = 146/54 = 2.70 g/cm^3
3: Volume = (27.8 -21.2) cm^3
mass = 22.4 g
density = 22.4/(27.8-21.2) g/cm^3

</span>
3 0
2 years ago
Read 2 more answers
(A) A chemical reaction takes place in a container of cross-sectional area 100 cm2. As a result of the reaction, a piston is pus
balandron [24]

Answer:

(A) The work done by the system is -101.325J

(B) The workdone by the system is -90.75J

Explanation:

(A) Workdone = -PΔV

Given that A = 100cm2 = 0.01m2

distance d = 10cm = 0.1m

ΔV= Area × distance

ΔV= 0.01 ×0.1

ΔV = 0.001m3

P= external pressure = 1atm = 101325Pa

Workdone = -0.001 × 101325

W= - 101.325Pa m3

1Pam3 = 1J

Therefore W = - 101.325J

The work done on the system is -101.325J

(B) Workdone = -PΔV

Given that A = 50cm2 = 0.005m2

distance d = 15cm = 0.15m

ΔV= Area × distance

ΔV= 0.005×0.15

ΔV = 0.00075m3

P=121kPa = 121000Pa

W= - 121000 × 0.00075

W= -90.75Pa m3

1Pam3 = 1J

W = - 90.75J

The woekdone by the system is -90.75J

5 0
2 years ago
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