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2 years ago

Where are some places that cyber bullying occurs? Check all that apply

Physics

1 answer:

horsena [70]2 years ago

5 0

Answer:

B, E, F

Explanation:

Because cyberbullying happens online, text messages, social media networks, and chat rooms can all have cyberbullying, because they are all ways to chat online. D does not apply, because on most websites there are not ways to chat.

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A bicyclist is riding at a tangential speed of 13.2 m/s around a circular track. The magnitude of the centripetal force is 377 N

MA_775_DIABLO [31]

Answer:

40m approximately

Explanation:

Given

Force =377N

Mass =86.5kg

Velocity =13.2m/s

Required

Radius of the track

The expression for the centripetal force acting on the cyclist is

F=mv²/r

Make r subject of the formula

r= mv²/F

Substitute

r=86.5*13.2²/377

r= 15,071.76/377

r=39.97

r=40m approximately

4 0

2 years ago

The 12.2-m crane weighs 18 kn and is lifting a 67-kn load. the hoisting cable (tension t1) passes over a pulley at the top of th

charle [14.2K]

I can't seem to figure out the angle between T1 and T2. So suppose, it is 10º; then T2 makes an angle of 35º w/r/t horizontal, and T1 makes an angle of 45º.
Sum the moments about the base of the crane; Σ M = 0. 0 = T2*cos35*L*cos40 + T1*cos45*L*cos40 - T2*sin35*L*sin40 - T1*sin45*L*sin40 - W*(L/2)*sin40 - T1*L*sin40 → length L cancels where W = 18 kN
0 = 0.259*T2 - 43kN T2 = 166 kN

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2 years ago

If the surface temperature of that person's skin is 30∘C (that's a little lower than healthy internal body temperature becaus

anastassius [24]

Answer:

$E=477.92\ W.m^{-2}$

Explanation:

Given that:

Absolute temperature of the body, $T=273+30=303\ K$

emissivity of the body, $\epsilon=1$

<u>Using Stefan Boltzmann Law of thermal radiation:</u>

$E=\epsilon. \sigma.T^4$

where:

$\sigma =5.67\times 10^{-8}\ W.m^{-2}.K^{-4}$ (Stefan Boltzmann constant)

Now putting the respective values:

$E=1\times 5.67\times 10^{-8}\times 303^4$

$E=477.92\ W.m^{-2}$

5 0

2 years ago

A pendulum is used in a large clock. The pendulum has a mass of 2kg. If the pendulum is moving at a speed of 2.9 m/s when it rea

Vanyuwa [196]

You first us 1/2(mv^2) to solve for the potential energy and then put that in to PE=m*g*h and solve for hight

3 0

2 years ago

Read 2 more answers

An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i

Butoxors [25]

Answer: $5 m/s^{2}$

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)