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2 years ago

Where are some places that cyber bullying occurs? Check all that apply

Physics

1 answer:

horsena [70]2 years ago

5 0

Answer:

B, E, F

Explanation:

Because cyberbullying happens online, text messages, social media networks, and chat rooms can all have cyberbullying, because they are all ways to chat online. D does not apply, because on most websites there are not ways to chat.

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What is the magnitude of the acceleration that is produced when the brakes of a 2.4 x 103 kg car apply a 3.2 x 103 N force to st

andriy [413]

Answer:

B 1.3 m/s2

Explanation:

Newton's second law of motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force. This in form of an equation is F = m*a

Since you want to know the acceleration, you have to solve for a

F = m*a

a = F / m

and now you substitute the data

a = 3.2x10^3 N / 2.4x10^3 kg

a = 1.3 m/s^2

4 0

2 years ago

Using a density of air to be 1.21kg/m3, the diameter of the bottom part of the filter as 0.15m (assume circular cross-section),

salantis [7]

Answer:

The drag coefficient is $D_z = 1.30512$

Explanation:

From the question we are told that

The density of air is $\rho_a = 1.21 \ kg/m^3$

The diameter of bottom part is $d = 0.15 \ m$

The power trend-line equation is mathematically represented as

$F_{\alpha } = 0.9226 * v^{0.5737}$

let assume that the velocity is 20 m/s

Then

$F_{\alpha } = 0.9226 * 20^{0.5737}$

$F_{\alpha } = 5.1453 \ N$

The drag coefficient is mathematically represented as

$D_z = \frac{2 F_{\alpha } }{A \rho v^2 }$

Where

$F_{\alpha }$ is the drag force

$\rho$ is the density of the fluid

$v$ is the flow velocity

A is the area which mathematically evaluated as

$A = \pi r^2 = \pi \frac{d^2}{4}$

substituting values

$A = 3.142 * \frac{(0.15)^2}{4}$

$A = 0.0176 \ m^2$

Then

$D_z = \frac{2 * 5.1453 }{0.0176 * 1.12 * 20^2 }$

$D_z = 1.30512$

3 0

1 year ago

Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol

sammy [17]

Grandparent and grandchild

7 0

2 years ago

Read 2 more answers

An elevator has a weight of 14,700 N and has an acceleration of –0.30 m/s2. The free-body diagram shows the forces acting on the

qwelly [4]

14250. I just took it

4 0

2 years ago

Read 2 more answers

Because the sensitivity of the human ear varies over the audio spectrum, how do many sound systems handle very high frequencies

antoniya [11.8K]

Answer:

Option 2.

Amplify; Amplify

Explanation:

Amplification of sound simply means increasing the loudness of the sound by modifying its electro-acoustic signals. To make very high and very low frequencies of sound audible by the human ear, the sounds need to be amplified by the sound system amplifier.

Sound systems modify high frequencies by amplifying them, and also, they also modify low frequencies by amplifying them. This changes their wave form and brings them into the hearing range of humans.

3 0

2 years ago