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Annette [7]
2 years ago
12

Calculate the mass of dinitrogen tetroxide(N2O4) that contains a billion oxygen atoms. Be sure your answer has a unit symbol if

necessary, and round it to significant digits.
Chemistry
1 answer:
Sati [7]2 years ago
3 0

Answer:

23 * 10^ 9 atoms of oxygen

Explanation:

From the molecular formula of dinitrogen tetraoxide;

molar mass of dinitrogen tetraoxide = 92 g/mol

hence;

92 g of dinitrogen tetraoxide contains 4 atoms of oxygen

x g of dinitrogen tetraoxide will contain 1 * 10^ 9 atoms of oxygen

x = 92 * 1 * 10^ 9/4

x =23 * 10^ 9 atoms of oxygen

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A column is filled with four different liquids of different densities. A red liquid, a blue liquid, a green liquid, and a purple
zhuklara [117]
4. Blue, Red, Green, Purple

(Lowest densities on the top, highest densities on the bottom)
7 0
2 years ago
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The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Molodets [167]

Answer:

Explanation:

The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin. Calculate the vapor pressure of the solution at 25 °C when 14.88 grams of aspirin, C9H8O4 (180.1 g/mol), are dissolved in 269.2 grams of diethyl ether. diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.

mol of C4H10O = mass of C4H10O / molar mass of C4H10O

= 242.1 g / 74.12 g/mol

= 3.266 mol

mol of C9H8O4 = mass of C9H8O4 / molar mass of C9H8O4

= 10.33 g / 180.1 g/mol

= 0.05736 mol

mole fraction of C4H10O,

X = mole of CHH1O0 / total mol

= (3.266)/(3.266 + 0.05736)

= 0.9827

now use:

P = Po*X

P = 463.57 * 0.9827

= 455.6 mm Hg

3 0
2 years ago
A galvanic cell employs the reaction Mg2+(aq) + Cu(s) → Mg(s) + Cu2+(aq) and NaNO3 is the salt used in the salt bridge. During t
sveta [45]

Answer:

b. Na+ leaves the salt bridge and enters enters the cathode

Explanation:

A galvanic cell or electrochemical cell depicts an oxidation -reduction half reactions (redox) reaction. it consists of two half cells ; one for the reduction reaction which involves the gain of electrons and the other for the oxidation reaction which involves the loss of electrons.  One half cell contains the anode and oxidation occurs at the anode while the other half cell contains the cathode and reduction occurs at the cathode. The anode is usually connected to the cathode, a salt bridge is added to complete the circuit and allow current to flow. The salt bridge serves as a counter ions, they do not interfere with the electrochemical reaction but provides a passage for the migration of ions thereby preventing the cells from reaching equilibrium too quickly and thus the electrons in the salt are able to move along with any electrons.

In this galvanic cell, Cu at the anode losses two electrons to become Cu2+, and the electrons moves from the anode to the cathode where Mg2+ gain these two electrons to become negatively charged. Positively charged ions in the salt brigde Na+ will move to the cathode to pick negatively charged ions from the cathode solution. this helps to remove the strong negative charge from the cathode and allows the electrons to continue to move to the cathode.

8 0
2 years ago
a.) The diameter of a uranium atom is 3.50 Å . Express the radius of a uranium atom in both meters and nanometers. b.) How many
Svetradugi [14.3K]

Answer:

Th answer to your question is:

a)  3.5 x10⁻¹⁰ meters; 0.35 nm

b) 6857142.86 atoms

c) Volume = 2.06 x 10⁻²³ cm³

Explanation:

a) data

Uranium atoms = 3.5A°

meters

           1 A° ----------------  1 x 10 ⁻¹⁰ m

         3.5A° ---------------  x

 x = 3.5(1 x10⁻¹⁰)/ 1 = 3.5 x10⁻¹⁰ meters

          1 A° ------------------ 0.1 nm

        3.5 A° ---------------- 0.35 nm

b) 2.4 mm

Divide 2,40 mm / uranium diameter

But, first convert 3,5A° to mm   = 3.5 x 10⁻⁷ mm

# of uranium atoms = 2.4 / 3.5 x 10⁻⁷ = 6857142.86

c) volume in cubic cm

Convert 3.5A° to cm  = 3.5 x 10⁻⁸

Volume = 4/3 πr³ = (4/3) (3.14)(1.7 x10⁻⁸)³

Volume = 2.06 x 10⁻²³ cm³

6 0
2 years ago
10.0 mL of a 0.100 mol L–1 solution of a metal ion M2+ is mixed with 10.0 mL of a 0.100 mol L–1 solution of a substance L. The f
Mrac [35]
The chemical reaction is
<span>                                 M2+(aq) + 2L(aq) <==> ML22+(aq)
</span>Intial concentration   0.10           0.10        
Change                       -x              -2x               +x
Equilibrium                0.10 - x    0.01 = 0.10 - 2x  x
Solving for x
0.01 = 0.10 - 2x
x = 0.045
The equilibrium concentration of ML22+ is 0.045 mol L-1


7 0
2 years ago
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