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garik1379 [7]
1 year ago
13

Products or solutions found at home or in store and their characteristics

Chemistry
1 answer:
AleksAgata [21]1 year ago
4 0

Answer:

bruh, just go in your bathroom and look for cleaning products

Explanation:

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Calculate the pH of the 1L buffer composed of 500 mL 0.60 M acetic acid plus 500 mL of 0.60 M sodium acetate, after 0.010 mol of
Ilia_Sergeevich [38]

Answer:

pH = 4.79

Explanation:

The pH of the acetic buffer can be determined using H-H equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa is -logKa = 4.76</em>

pH = 4.76 + log [sodium Acetate] / [Acetic Acid]

<em>Where [] can be taken as moles of each specie.</em>

Thus, to find pH of the buffer we need to calculate molesof acetic acid and sodium acetate.

<em>Initial moles:</em>

Initial moles of acetic acid and sodium acetate are:

500mL = 0.500L ₓ (0.60moles / L) = 0.30 moles of both acetic acid and sodium acetate

<em>Moles after reaction:</em>

Now, 0.010 moles of NaOH are added to the buffer reacting with acetic acid, CH₃COOH, producing more acetate ion, as follows:

NaOH + CH₃COOH → CH₃COO⁻ + H₂O

That means after reaction moles of both species are:

Acetic acid: 0.30mol - 0.010mol (Moles that react) = 0.29 moles

Acetate: 0.30mol + 0.010mol (Moles produced) = 0.31 moles

Replacing in H-H equation:

pH = 4.76 + log [0.31] / [0.29]

<h3>pH = 4.79</h3>

<em />

6 0
1 year ago
Compound w , c6h13cl, undergoes base-promoted e2 elimination to give a single c6h12 alkene, y. compound x, c6h13br, undergoes a
CaHeK987 [17]
<span>Answer: W must be 5-chloro-2-methylpentane. It can give only 4-methy-1-pentene (Y) upon dehydrohalogenation: X must be 4-chloro-2-methylpentane. Dehydrohalogenation yields both Y and 4-methyl-2-pentene. (Z)</span>
5 0
2 years ago
Consider the following incomplete reaction. Mg + 2Y ---&gt; MgCl₂ + H₂ Choose the formula for the missing substance Y.
vesna_86 [32]
It would be B as the answer
7 0
1 year ago
To maximize the yield in a certain manufacturing process, a solution of a weak monoprotic acid that has a concentration between
stira [4]

Answer: C 115 ml

Explanation:

If you have a solution of a monoprotic acid, it means that it has the form HA (just one Hydrigen atom). Therefore, one molecule of acid is going to react with just one molecule of  NaOH.

So, if you have a solution of 100 ml of 0,2 HA acid, it is going to react with a 100 ml of 0,2 M NaOH solution. Beacause we know that the acid can be a little more concentrated than 0,2 M (0,2-0,3), it probably needs a little more than 100 ml of NaOH to react.  So, the answer is C.

in 100 ml of 0,2M acid you can find 0,002 mol of HA

in 100 ml of 0,3 M acid you can find 0,003 mol of HA

in 100 ml of 0,2 M NaOH you can find 0,002 mol of NaOH

the answer can not be 200 because in 200 ml of 0,2 M NaOH there are 0,004 mol of NaOH, which is more than 0,003 mol.

0 0
2 years ago
What is the oxidation state of selenium in SeO3?​
ra1l [238]

Answer: The oxidation state of selenium in SeO3 is +6

Explanation:

SeO3 is the chemical formula for selenium trioxide.

- The oxidation state of SeO3 = 0 (since it is stable and with no charge)

- the oxidation number of oxygen (O) IN SeO3 is -2

- the oxidation state of selenium in SeO3 = Z (let unknown value be Z)

Hence, SeO3 = 0

Z + (-2 x 3) = 0

Z + (-6) = 0

Z - 6 = 0

Z = 0 + 6

Z = +6

Thus, the oxidation state of selenium in SeO3 is +6

8 0
2 years ago
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