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il63 [147K]
2 years ago
14

A 20.0-kg uniform plank (10.0 m long) is supported by the floor at one end and by a vertical rope at the other as shown in the f

igure. A 50.0-kg mass person stands on the plank a distance three-fourths of the length plank from the end on the floor.
Physics
1 answer:
Nataly [62]2 years ago
7 0

Answer:

Tension= 475N

Force= 225N

Explanation:

The question is not complete, here is the complete question

Also, see attached a free body diagram for your reference

<em>"A 20.0-kg uniform plank is supported by the floor at one end by a vertical rope at the other as shown in the figure. A 50.0-kg mass person stands on the plank a distance three-fourths of the length plank from the end on the floor. </em>

<em>a. What is the tension in the rope? </em>

<em>b. What is the magnitude of the force that the floor exerts on the plank?"</em>

<em />

given data

mass of man=50kg

mass of plank=20kg

length of plank=10m

<em />

let us make the lenght of the rope be d

The torque about the floor

That is taking moment about the floor

N*0+T*d=20*10*d/2 + 50*10*3d/4\\\\T=100+375=475N\\\\

Force will be also zero  

N+T=20*10+50*10\\\\N+T=700 \\\\N=700-475=225 newtons\\\\N+T=20*10+50*10\\\\N+T=700\\\\N=700-475=225newtons

<em />

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