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2 years ago

A 11.0 kg iron weightlifting plate has a volume of 1400 cm3 . What is the density of the iron plate in g/cm3?

1 answer:

5 0

The easy part about this question is that it already gives you the equation to use. If you're trying to find the weight in g/cm^3, all you have to do is divide the weight in grams (g) by the volume in cubic centimeters (cm^3).

The problem already gives you the volume, so you just need to convert kilograms (kg) into grams (g).

Hint: "kilogram" means 1000 grams. There are 1,000 grams in each kilogram.

So find the weight of the object in grams, then divide that number by the volume in cm^3.

You might be interested in

Enter the correct answer for each unit conversion.

Luden [163]

Answer:

50 mm

4 ft

36 ft

250 cm

1 L

Explanation:

Centimeter to millimeter:

1 cm is equal to 10 mm.

5cm× 10 mm/1 cm

50 mm

Inches to feet conversion:

1 foot is equal to 12 inches.

48 inch × 1 feet /12 inch

4 feet

Yard to Feet conversion:

1 yard is equal to 3 feet.

12 yd × 3 ft / 1 yd

36 ft

Meter to centimeter:

One meter is equal to 100 cm.

2.5 m × 100 cm / 1m

250 cm

Milliliter to Liter:

One L is equal to 1000 mL.

1000 mL = 1 L

4 0

1 year ago

Read 2 more answers

The ΔG for a particular enzyme-catalyzed reaction is -20 kcal/mol. If the amount of enzyme in the reaction is doubled, what will

LUCKY_DIMON [66]

Answer:

The value of the of ΔG for the new reaction will be same as the given value of -20kcal/mol.

Explanation:

In an enzyme-catalyzed reaction, the concentration or amount of enzyme will not affect the equilibrium constant of the reaction due to which ΔG for the reaction will remain unaffected. Here enzymes are acting as a catalyst that cannot alter law thermodynamics and equilibrium of the reaction.

$\Delta G=\Delta G^o+RT\ln K_{eq}$

Since the enzyme amount will not affect the equilibrium of the reaction, the value of ΔG will remain the same as given -20 kcal/mol.

3 0

2 years ago

Based on the bond energies for the reaction below, what is the enthalpy of the reaction?HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O

Anuta_ua [19.1K]

Answer:

1219.5 kj/mol

Explanation:

To reach this result, you must use the formula:

ΔHºrxn = Σn * (BE reactant) - Σn * (BE product)

ΔHºrxn = [1 * (BE C = C) + 2 * (BE C-H) + 5/2 * (BE O = O)] - [4 * (BE C = O) + 2 * (BE O-H).

The BE values are:

BE C = C: 839 kj / mol

BE C-H: 413 Kj / mol

BE O = O: 495 kj / mol

BE C = O = 799 Kj / mol

BE O-H = 463 kj / mol

Now you must replace the values in the above equation, the result of which will be:

ΔHºrxn = [1 * 839 + 2 * (413) + 5/2 * (495)] - [4 * (799) + 2 * (463) = 1219.5 kj/mol

8 0

2 years ago

Both black and white road surfaces radiate energy. at midnight on a starry night the warmer road surface is the

luda_lava [24]

The black road because during the day it absorbed more radiation than the with one

5 0

1 year ago

The incomplete table below shows selected characteristics of gas laws.

Elenna [48]

Explanation :

In the given case different law related to gas is given. The attached figure shows the required solution.

Boyle's law states that the pressure is inversely proportional to the volume of the gas i.e.

$P\propto \dfrac{1}{V}$

$PV=k$

k is a constant.

Charle's law states that the volume of directly proportional to the temperature of the gas.

$V\propto T$

$V=kT$

Combined gas law is the combination of the pressure, volume and the temperature of the gas i.e.

$\dfrac{PV}{T}=k$

Hence, this is the required solution.

6 0

2 years ago

Read 2 more answers