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kirza4 [7]
2 years ago
14

1. Susie wondered if the height of a hole punched in the side of a quart-size milk carton would affect how far from the containe

r a liquid would spurt when the carton was full of the liquid. She used 4 identical cartons and punched the same size hole in each. The hole was placed at a different height on one side of each of the containers. The height of the holes varied in increments of 5 cm, ranging from 5-20 cm from the base of the carton. She put her finger over the holes and filled the cartons to a height of 25 cm with a liquid. When each carton was filled the proper level, she placed it in the sink and removed her finger. Susie measured how far away from the carton’s base the liquid had squirted when it hit the bottom of the sink.
Hypothesis:
Independent Variable:
Dependent Variable:
Constant (at least one):
Control:
Number of groups:
Number of trials per group:
Physics
2 answers:
sdas [7]2 years ago
7 0
Hypothesis: The water will squirt far.
Indep.V.: Height of hole.
Depend.V.: Range of squirt
Constant: Everything that isnt the independant var. such as filled liquid.
Control: None,I believe.
Number of groups: 4
Trials per group: 4
zheka24 [161]2 years ago
6 0

Answer:

A scientific experiment is performed to test the hypothesis which is the predicted idea about the natural phenomenon based on the previous research.

The experimental design must contain three types of variables: the variable which can be manipulated  (independent variable). the variable which is to be tested (dependent variable) and the variable which is kept constant throughout the experiment (constant variable).

The experimental sample is divided into two groups: the experimental group which includes the factor to be studied and the control group which lack the factor to be studied.

In the given question,

1. Hypothesis:  liquid spurt when falls form a height.

2. Independent Variable:  Height of hole which gets changed

3. Dependent Variable:  Range of squirt which is to be tested

4. Constant (at least one):the volume of filled liquid is kept constant

5. Control: 4 identical cartons which are punched with a hole of the same size.

6. A number of groups:  two (control and experimental)

7. Number of trials per group: four

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13. An aircraft heads North at 320 km/h rel:
AURORKA [14]

The velocity of the aircraft relative to the ground is 240 km/h North

Explanation:

We can solve this problem by using vector addition. In fact, the velocity of the aircraft relative to the ground is the (vector) sum between the velocity of the aircraft relative to the air and the velocity of the air relative to the ground.

Mathematically:

v' = v + v_a

where

v' is the velocity of the aircraft relative to the ground

v is the velocity of the aircraft relative to the air

v_a is the velocity of the air relative to the ground.

Taking north as positive direction, we have:

v = +320 km/h

v_a = -80 km/h (since the air is moving from North)

Therefore, we find

v'=+320 + (-80) = +240 km/h (north)

Learn more about vector addition:

brainly.com/question/4945130

brainly.com/question/5892298

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7 0
2 years ago
A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2

So, the acceleration of the hockey puck is 190\ m/s^2.

5 0
2 years ago
Plug variables expressed in SI units in the kinematic equation given in article: a = -v0^2/(2sg). What value of g you get as exp
Elanso [62]

Answer:

1) acceleration is increased by a factor of four 4X

2) the acceleration increases a factor of 2X

3) the correct answer of 400g

Explanation:

This is a kinematics exercise, where you use the velocity equation to obtain the acceleration, with the final velocity equal to zero.

           v² = v₀² + 2 a x

           0 = v₀² + 2 a x

           a = - v₀² / 2 x

           

In the case of wanting to give the acceleration as a function of g, we can find the relationship between the two quantities

         a / g = - v₀² / (2 x g)

Let's answer the different questions about this equation

1. The initial velocity is doubled, how much the acceleration is worth

           

       a/g = - (2v₀) 2 / 2xg

       a = 4 (-v₀² / 2xg) g

acceleration is increased by a factor of four 4X

2. if the stopping distance is reduced by 2, that is, x = x₀ / 2

we substitute

        a/g = (- v₀² / 2g) 2/x

         

        a =2  (-v₀² / 2x₀g)  g

       

therefore the acceleration increases a factor of 2X

3. the initial velocity of the hockey player is v₀ = 20 m / s and the stopping distance is

x = 5cm = 0.05m

we calculate the acceleration

        a / g = - 20² / (2 0.05)

        a / g = - 4000 / g

        a / g = - 4000 / 9.8 = 408

        a = 408 g

the correct answer of 400g, the value matches exactly if g = 10 m / s2 is taken

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snow_lady [41]

Answer:

3.8%

Explanation:

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