Answer:
h = v₀² / 2g
, h = k/4g x²
Explanation:
In this exercise we can use the law of conservation of energy at two points, the lowest, before the shot and the highest point that the mouse reaches
Starting point. Lower compressed spring
Em₀ = K = ½ m v²
Final point. Highest on the path
= U = mg h
As or no friction the energy is conserved
Em₀ = Em_{f}
½ m v₀²² = m g h
h = v₀² / 2g
We can also use as initial energy the energy stored in the spring that will later be transferred to the mouse
½ k x² = 2 g h
h = k/4g x²
Answer:
0.02
Explanation:
coefficient of kinetic friction = μ
force of friction = Ff
Normal Force = FN, but
FN = -W
Ff = -μFN
so μ = Ff/FN
= 4N/200N
= 0.02.
Complete question:
A dog runs 3 miles east and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?
Answer:
The total distance covered by the dog is 7 miles
The displacement of the dog is 1 mile west
Explanation:
Given;
initial position of the dog = 3 miles east
final position of the dog = 4 miles west
time of motion, t = 6 hours
The total distance covered by the dog is given as;
Total distance = 3 miles + 4 miles = 7 miles
The displacement of the dog is given as;
displacement = final position of the dog - initial position of the dog
displacement = 4 miles west - 3 miles east = 1 mile west
Answer:
2805 °C
Explanation:
If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:
The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.
In the initial situation the gas have an initial volume 
, temperature 
, and pressure 
,.
And in the final situation the gas have different volume 
and temeperature 
, the same pressure ,, and the same number of moles 
,.
We can write the gas ideal equation for each state:
and 
, as the pressure are equals in both states we can write
solving for
(*)
We know = 935 °C, and that the (the complete volume of the tank) is the initial volume plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume 
Replacing in (*)
