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Ber [7]
2 years ago
3

You have negotiated with the Omicronians for a base on the planet Omicron Persei 7. The architects working with you to plan the

base need to know the acceleration of a freely falling object at the surface of the planet in order to adequately design the structures. The Omicronians have told you that the value is gOP7=7.29 flurg/grom^2, but your architects use the units meter/second^2, and from your previous experience you know that both the Omicronians and your architects are terrible at unit conversion. Thus, it's up to you to do the unit conversion. Fortunately, you know the unit equality relationships: 5.24 flurg=1 meter and 1 grom=0.493 second. What is the value of gOP7 in the units your architects will use, in meter/second^2?
Physics
1 answer:
Inga [223]2 years ago
3 0
<span>5.72 m/s^2 First, we have available 2 conversion units. 5.24 flurg/m and 0.493 s/grom I chose the units to describe those two conversions by making the denominator equal to 1 in both cases, so there are 5.24 flurgs per meter and 0.493 seconds per grom. Now we've been given 7.29 flurg/grom^2 and we want to convert to m/s^2. So we need to figure out how to multiply or divide our conversion factors to cancel out the flurg and grom units. Let's see about cancelling the flurg unit 1st and replacing it with meters Let's try multiplication flurg/grom^2 * flurg/m = flurg^2/(m*grom^2) That won't work. So let's try division flurg/grom^2 / flurg/m = flurg/grom^2 * m/flurg = (m*flurg)/(grom^2 * flurg) The flurg on top and bottom, cancel, so = m/grom^2 So dividing by our length conversion will work correctly. Let's do it. 7.29 flurg/grom^2 / 5.24 flurg/m = 1.391221374 m/grom^2 Now we want to convert from m/grom^2 to m/(s grom) using our time conversion factor. Since we want s in the denominator and it's in the numerator, a division looks good. So m/grom^2 / s/grom = m/grom^2 * grom/s = (m*grom)/(grom^2 * s) = m/(grom * s) And it is good. So let's do it 1.391221374 m/grom^2 / 0.493 s/grom = 2.821950049 m/(grom s) We still have one more grom to get rid of. And since it's in the same place as the previous one, let's divide again. 2.821950049 m/(grom s) / 0.493 s/grom = 5.72403661 m/s^2 Since all our input is to only 3 significant figures, round the result to 3 significant figures. Giving 5.72 m/s^2</span>
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A thin ring of radius 73 cm carries a positive charge of 610 nC uniformly distributed over it. A point charge q is placed at the
kow [346]

Answer:

q = - 93.334 nC

Explanation:

GIVEN DATA:

Radius of ring  73 cm

charge on ring 610 nC

ELECTRIC FIELD p FROM CENTRE IS AT 70 CM

E  =  2000 N/C

Electric field due tor ring is guiven as

E = \frac{KQx}{[x^2+ R^2]^{3/2}}

E = \frac{9\time 10^9 \times 610\times 10^[-9} 0.70}{(0.70^2 + 0.73^2)^{3/2}}

E1 = 3714.672 N/C

electric field due to point charge q

E  =\frac[kq}{x^2}

E = \frac{9\times 10^9 \times q}{0.70^2}

E2 = 1.837\times 10^{10}\times q

now the eelctric charge at point P is

E = E1 + E22000 =  3714.672 + 1.837\times 10[10} \times q

solving for q

q = - 93.334 nC

7 0
2 years ago
A boat moves through the sea.
sergiy2304 [10]

Answer:

dont you have to times it

Explanation:

4 0
2 years ago
What is the radius of an automobile tire that turns with a period of 0.091 s and has a linear
faust18 [17]

Answer:

1) The radius of the tire is approximately 0.28966 meters

2) The centripetal force is the force that keeps a body moving on a circular path

Explanation:

1) The linear speed of the automobile tire = 20.0 m/s

The period with which the tire turns = 0.091 s

The period = The time it takes to make a complete turn

Therefore;

The number of turns in 1 second = 1/0.091 ≈ 10.989 turns

The distance covered with 10.989 turns, assuming no friction = 10.989 × The circumference of the tire

∴ The distance covered with 10.989 turns, assuming no friction = 10.989 × 2 × π × Radius of the tire

From the speed of the car, 20.0 m/s, we have;

The distance covered in 1 second = 20.0 meters

Therefore;

10.989 × 2 × π × Radius of the tire = 20.0 meters

Radius of the tire = (20.0 meters)/(10.289 × 2 × π) ≈ 0.28966 meters

The radius of the tire ≈ 0.28966 meters

2) The centripetal force is the force required to maintain the curved motion of an object, and having a direction towards the center of the rotary motion.

The centripetal force is given by the formula, F = \dfrac{m \cdot v^2}{r}

Where;

F = The centripetal force

m = The mass of the object

v = The linear velocity of the object

r = The radius of the rotational motion.

3 0
2 years ago
A rectangular conducting loop of wire is approximately half-way into a magnetic field B (out of the page) and is free to move. S
Black_prince [1.1K]

Answer:

. The loop is pushed to the right, away from the magnetic field

Explanation

This decrease in magnetic strength causes an opposing force that pushes the loop away from the field

8 0
2 years ago
A physics student walks 100 meters in 80 seconds. The student stops for 30 seconds, and then walks 200 meters farther in 90 seco
Elan Coil [88]

Answer:

B i think is the answer

Explanation:

i feel like it is B because if you put them together and the answer is 1.5 so it is B

8 0
2 years ago
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