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omeli [17]
1 year ago
15

A container filled with gas is connected to an open-end manometer that is filled with mineral oil. the pressure in the gas conta

iner is 753 mm hg and atmospheric pressure is 724 mm. how high will the level rise in the manometer if the densities of hg and mineral oil are 13.6 g/ml and 0.822 g/ml respectively?
Chemistry
1 answer:
Vesnalui [34]1 year ago
3 0
<span>The difference in pressure is equal to the pressure exerted by the displaced fluid. Since the Pressure difference is equal, density of fluid is inversely proportional to the height of the column of displaced fluid => (Ď1)(h1) = (Ď2)(h2) (13.6 g/ml)(753 - 724 mm Hg) = (0.822 g/ml)(h2) h2 = (13.6 g/ml)(753 - 724 mm Hg) / (0.822 g/ml) h2 = 480 mm</span>
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V₂ = 15.6 L

Explanation:

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7 0
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vekshin1
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Answer:

La cantidad de yodo en la muestra es 0.217 g

Explanation:

Los parámetros dados son;

Normalidad de la solución de Na₂S₂O₃ = 0.1 N

Volumen de la solución de Na₂S₂O₃ = 17.1 mL

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La ecuación de reacción química se da de la siguiente manera;

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Por lo tanto, el número de moles de sodio por 1 mol de Na₂S₂O₃ en la reacción = 1 mol

Por lo tanto, la normalidad por mol = 1 M × 1 átomo de Na = 1 N

Por lo tanto, 0.1 N = 0.1 M

El número de moles de Na₂S₂O₃ en 17,1 ml de solución 0,1 M de Na₂S₂O₃ se da de la siguiente manera;

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Lo que da;

Un mol de yodo, I₂, reacciona con dos moles de Na₂S₂O₃

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La masa molar de yodo = 253.8089 g / mol

La masa de yodo en la muestra = 253.8089 × 0.000855 = 0.217 g.

5 0
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