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omeli [17]
2 years ago
15

A container filled with gas is connected to an open-end manometer that is filled with mineral oil. the pressure in the gas conta

iner is 753 mm hg and atmospheric pressure is 724 mm. how high will the level rise in the manometer if the densities of hg and mineral oil are 13.6 g/ml and 0.822 g/ml respectively?
Chemistry
1 answer:
Vesnalui [34]2 years ago
3 0
<span>The difference in pressure is equal to the pressure exerted by the displaced fluid. Since the Pressure difference is equal, density of fluid is inversely proportional to the height of the column of displaced fluid => (Ď1)(h1) = (Ď2)(h2) (13.6 g/ml)(753 - 724 mm Hg) = (0.822 g/ml)(h2) h2 = (13.6 g/ml)(753 - 724 mm Hg) / (0.822 g/ml) h2 = 480 mm</span>
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Nataliya [291]

Answer:

pH reducing agent for acidic soils

Explanation:

Gypsum is not used to reduce soil pH because it will displace the soil H+ but there's no means of extracting the H from the soil. So the pH of the soil remains the same.

3 0
2 years ago
If the actual yield of the reaction was 75% instead of 100%, how many molecules of no would be present after the reaction was ov
artcher [175]
To be able to answer this equations, we must set given information. Suppose the reaction to yield NO is:

N₂ + O₂ → 2 NO

Next, suppose you have 1 g of each of the reactants. Determine first which is the limiting reactant.

1 g N₂ (1 mol N₂/ 28 g)(2 mol NO/1 mol N₂)= 0.07154 mol NO present

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<em>Number of molecules = 4.3×10²² molecules NO present</em>
8 0
2 years ago
Read 2 more answers
What is the final pressure (expressed in atm) of a 3.05 l system initially at 724 mm hg and 298 k, that is compressed to a final
krok68 [10]

<u>Answer:</u>

P2 = 778.05 mm Hg = 1.02 atm

<u>Explanation:</u>

We are to find the final pressure (expressed in atm)  of a 3.05 liter system initially at 724 mm hg and 298 K which is compressed to a final volume of 2.60 liter at 273 K.

For this, we would use the equation:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

where P1 = 724 mm hg

V1 = 3.05 L

T1 = 298 K

P2 = ?

V2 = 2.6 L

T2 = 173 K

Substituting the given values in the equation to get:

\frac{(724)(3.05)}{298} =\frac{P_2(2.6)}{173}

P2 = 778.05 mm Hg = 1.02 atm

7 0
2 years ago
Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 669.1-g sam
Vedmedyk [2.9K]

Answer:

2.4 ×10^24 molecules of the herbicide.

Explanation:

We must first obtain the molar mass of the compound as follows;

C3H8NO5P= [3(12) + 8(1) + 14 +5(16) +31] = [36 + 8 + 14 + 80 + 31]= 169 gmol-1

We know that one mole of a compound contains the Avogadro's number of molecules.

Hence;

169 g of the herbicide contains 6.02×10^23 molecules

Therefore 669.1 g of the herbicide contains 669.1 × 6.02×10^23/ 169 = 2.4 ×10^24 molecules of the herbicide.

7 0
2 years ago
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7 0
2 years ago
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