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kaheart [24]
2 years ago
11

determine whether each of the following causes an increase or decrease in the activity of the electron transport chain.

Chemistry
1 answer:
viktelen [127]2 years ago
4 0
The following causes increase the activity of the electron transport chain:
1. High ADP concentration
2. Large differences in H+ concentration across the inner mitochondrial membrane
3. High phosphate concentration

The following causes decrease the activity of the electron transport chain:
1. Low oxygen concentration
2. Low NADH concentration
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List the bonding pairs H and I; S and O; K and Br; Si and Cl, H and F; Se and S; C and H in order of increasing covalent charact
stellarik [79]

Answer:

1. (S,O) < (Se,S) < (C,H) = (H,I) = (H,F) < (Si,Cl) < (K,Br)

Explanation:

The covalent character always increases down the group, this is because ionic character decreases down the group and also electronegativity.

In the same way, Covalent character always decreases across a period because electronegativity increases across a period.

The higher the electronegativity values between the two atoms, the more ionic it will be.

5 0
2 years ago
Which of the following yields a basic solution when dissolved in water? I. Nh3 ii. Na2o iii. Lioh iv. P4o10
emmainna [20.7K]

<u>Answer:</u> The correct answer is Option 1, Option 2 and Option 3.

<u>Explanation:</u>

A base is defined as the substance which releases hydroxide ion when dissolved in water.

For the given options:

  • <u>Option 1:</u>  NH_3

When ammonia is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

NH_3+H_2O\rightarrow NH_4OH

  • <u>Option 2:</u>  Na_2O

When sodium oxide is dissolved in water, it produces ammonium hydroxide which forms a basic solution.

Na_2O+H_2O\rightarrow 2NaOH

  • <u>Option 3:</u>  LiOH

When lithium hydroxide is dissolved in water, it produces aqueous lithium hydroxide which forms a basic solution.

LiOH+H_2O\rightarrow LiOH(aq.)

  • <u>Option 4:</u>  P_4O_{10}

When phosphorus pentoxide is dissolved in water, it produces phosphoric acid which forms an acidic solution.

P_4O_{10}+6H_2O\rightarrow 4H_3PO_4

Hence, the correct answer is Option 1, Option 2 and Option 3.

8 0
2 years ago
Trans fats: Think about how the prefix trans- is used in naming alkenes.
wel
In an alkene, cis and trans isomers are possible because the double band is rigid, cannot rotate, has groups attached to the carbons of the double bond that are fixed relative to each other, and only occurs with double bonds-possibility that molecule will have different geometries; two different molecules with slightly different properties. 
-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
4 0
2 years ago
Read 2 more answers
You are given a piece of paper and a match. The paper has a mass of 2.5 g. You then light the match and light the piece of paper
kow [346]

Answer:

No

Explanation:

<em>No. </em>T<em>he demonstration does not violate the conservation of mass.</em>

<u>The law of conservation of mass states that mass can neither be created nor destroyed in a reaction. However, mass can be converted from one form to another during the reaction.</u>

In this case, even though the remaining bits of paper weigh 0.5 g while the original paper weighed 2.5 g, the ashes and smoke/gas from the burning will all add up to the lost weight of the paper.

<em>The burned part has been converted into other forms. If the smoke/gas and the ashes are properly captured, they will mark up with the weight of the remaining paper to give the weight of the original paper. </em>

5 0
2 years ago
it takes 151 kJ/mol to break an iodine-iodine single bond. calculate the maximum wavelength of light for which an iodine-iodine
Allisa [31]

Answer:

The wavelength of light require to brake an single I-I bond is  7.92 × 10⁻⁷ m

Explanation:

Amount of energy required to break the one mole of iodine-iodine single bond = 151 KJ

amount of energy to break one iodine -iodine bond = (151 KJ/mol )/ 6.02 × 10²³/mol = 2.51 × 10⁻²² KJ

or

2.51 × 10⁻¹⁹ J

Formula:

E = hc / λ    

h = planck's constant    = 6.626 × 10⁻³⁴ js

c = speed of light = 3 × 10⁸ m/s

λ = wavelength

Solution:

E = hc / λ  

λ   = hc / E

λ   =  (6.626 × 10⁻³⁴ js × 3 × 10⁸ m/s ) / 2.51 × 10⁻¹⁹ J

λ   = 19.878 × 10⁻²⁶ j .m / 2.51 × 10⁻¹⁹ J

λ   = 7.92 × 10⁻⁷ m

6 0
2 years ago
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