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Elena L [17]
2 years ago
13

A rigid tank having a volume of 0.100 m3 contains helium gas at 150 atm. how many balloons can be inflated by opening the valve

at the top of the tank? each filled balloon is a sphere 0.300 m in diameter at an absolute pressure of 1.20 atm
Physics
1 answer:
GalinKa [24]2 years ago
4 0
The initial value of P*V = 0.100*150 atm-m³ 
<span> Each balloon has a volume of (4/3)*π*r³ and N balloons have a volume of N*(4/3)*π*r³ 
</span><span> When all the balloons are inflated, the pressure in the tank is the same as the pressure in the balloons, so the final value of P*V is 
</span><span> 1.20*[N*(4/3)*π*r³ + 0.100] 
</span><span> 0.100*150 = 1.20*[N*(4/3)*π*r³ + 0.100] solve for N: 
</span><span> 15/1.2 = N*(4/3)*π*r³ + 0.100
</span><span> 12.5 - 0.100 = N*(4/3)*π*0.150³ 
</span><span> 12.4 = N*0.01414 
</span><span> N = 877</span>
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2 years ago
A satellite with a mass of 5.6 E 5 kg is orbiting the Earth in a circular path. Determine the satellite's velocity if it is orbi
solniwko [45]

Answer:

7500 m/s

Explanation:

Centripetal acceleration = gravity

v² / r = GM / r²

v = √(GM / r)

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.98×10²⁴ kg

r = 6.8×10⁵ + 6.357×10⁶ = 7.037×10⁶ m

v = √(6.67×10⁻¹¹ (5.98×10²⁴) / (7.037×10⁶))

v = 7500

The orbital velocity is 7500 m/s.

7 0
2 years ago
A uniform electric field with a magnitude of 125 000 N/C passes through a rectangle with sides of 2.50 m and 5.00 m. The angle b
jeyben [28]

Answer:

6.60\cdot 10^5 Nm^2/C

Explanation:

The electric flux through the rectangle is given by

\Phi = E A cos \theta

where

E is the electric field strength

A is the area of the rectange

\theta is the angle between the direction of the electric field and of the vector normal to the plane of the rectangle

In this problem we have

E = 125 000 N/C

The area of the rectangle is

A=2.50 m \cdot 5.00 m=12.5 m^2

and the angle is

\theta=65.0^{\circ}

so, the electric flux is

\Phi = (125,000 N/C)(12.5 m^2)(cos 65^{\circ})=6.60\cdot 10^5 Nm^2/C

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Answer:

<em>A.The rabbits in the new habitat will have lower genetic variation than the rabbits in the original habitat. </em>

<em></em>

Explanation:

If two animals of opposite sex are isolated from a larger group of animal, and made to reproduce. They will produce offspring with similar genetic makeup. If this offspring still remain isolated, and continue to interbreed within themselves for a number of consecutive generations, their offspring will all be very closely related genetically. Situations like this just as with the two rabbits in the question leads to a lower genetic variation within the offspring of the two animals.

Animals need to reproduce within a larger group in order to increase genetic variation. Increasing genetic variation reduces the risk of been sucked into a gene pool. A lower genetic variation reduces the fitness of the animals involved. It is only an advantage in cases in which the the original pair are resistant to a deadly disease. In this case all the offspring also develop this immunity. Mostly the effects of a lower genetic variation leaves negative impacts, and animals try to avoid this by preferring to interbreed with unrelated partner

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2 years ago
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