Since we are given the density and volume, then perhaps we can determine the amount in terms of the mass. All we have to do is find the volume in terms of cm³ so that it will cancel out with the cm³ in the density. The conversion is 1 ft = 30.48 cm. The solution is as follows:
V = (14 ft)(15 ft)(8 ft)(30.48 cm/1 ft)³ = 0.0593 cm³
The mass is equal to:
Mass = (0.00118g/cm³)(0.0593 cm³)
Mass = 7 grams of HCN
Answer:
16,18,22
Or
1,3,7
Explanation:
The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation
Answer:
The maximum transverse speed of the bead is 0.4 m/s
Explanation:
As we know that the Amplitude of the travelling wave is
A = 3.65 mm
Now the speed of the travelling wave is

now we know that distance of first antinode from one end is 27.5 cm
so length of the loop of the standing wave is given as


now we have



now we have



now at x = 13.8 cm


now we have



now maximum speed is given as



The concept used in this is circuit analysis using the simplification of resistors and capacitors.
Explanation:
The time constant for each of the circuits in figure A, B, C, D and E. Therefore, rank the length of time the bulbs stay lit from longest to shortest by using the value of time constant for each circuit. The rank of the time constant of the circuit is C > A = E > B > DC > A = E > B > D.
Capacitance is the central concept in electrostatics and constructed devices called capacitors are essential elements of electronic circuits.
If more charge is placed on the conductor the voltage increases proportionately. The ratio of the charge to the voltage is called the capacitance C of the conductor C= q/v.
The resistance increases if you add resistors in series and decreases if you add them in parallel. on the other hand the capacitors increases if it is added parallel and decreases if added in series. hence the circuit longest time constant takes longest time to discharge.
That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.