The second gas is identified as follows
by Graham law formula
let the unknown gas be represented by letter y
=time of effusion of Neon/ time of effusion of y = sqrt (molar mass of neon/molar mass of y)
= 72 sec/ 147 sec = sqrt( 20.18 g/mol/ y g/mol)
square the both side to remove the square root sign
72^2/147^2 = 20.18 g/mol/y g/mol
=0.24 = 20.18g/mol/y g/mol
multiply both side by y g/mol
= 0.24 y g/mol = 20.18g/mol
divide both side by 0.24
y = 84 g/mol
y is therefore Krypton since it is the one with a molar mass of 84 g/mol
Answer:
As
Explanation:
For any element to exhibit the pattern of ionization energy shown in the question, it must possess five electrons in its outermost shell. These five electrons are not lost at once. They are lost progressively until the valence shell becomes empty. The ionization energy increases steadily as more electrons are lost from the valence shell.
The only pentavalent element among the options in arsenic, hence the answer.
4) fission is a nuclear reaction where the nucleus of a reactant breaks apart
First, let us find the corresponding amount of moles H₂ assuming ideal gas behavior.
PV = nRT
Solving for n,
n = PV/RT
n = (6.46 atm)(0.579 L)/(0.0821 L-atm/mol-K)(45 + 273 K)
n = 0.143 mol H₂
The stoichiometric calculations is as follows (MW for XeF₆ = 245.28 g/mol)
Mass XeF₆ = (0.143 mol H₂)(1 mol XeF₆/3 mol H₂)(245.28 g/mol) = <em>11.69 g</em>
