Answer:
- asses disease progression and tissue function
- utilize a biologically active molecule
- utilize a radionuclide tracer
Explanation:
To solve this problem we will apply the concepts related to gravity according to the Newtonian definitions. From finding this value we will use the linear motion kinematic equations to find the time. Our values are
Comet mass 
Radius 
Rock was dropped from a height 'h' from surface = 1m
The relation for acceleration due to gravity of a body of mass 'm' with radius 'r' is

Where G means gravitational universal constant and M the mass of the planet


Now calculate the value of the time




The time taken for the rock to reach the surface is t = 87.58s
Fm=Fe and am>ae
Hopefully this helps
Answer:
The terminal speed of this object is 12.6 m/s
Explanation:
It is given that,
Mass of the object, m = 80 kg
The magnitude of drag force is,

The terminal speed of an object is attained when the gravitational force is balanced by the gravitational force.



On solving the above quadratic equation, we get two values of v as :
v = 12.58 m/s
v = -15.58 m/s (not possible)
So, the terminal speed of this object is 12.6 m/s. Hence, this is the required solution.
Answer:
Absolute error=0.006
Percentage Relative error=0.6
Explanation:
The resistors have resistance of 24 ohm and 8 ohm.
The change in resistance is 0.5 and 0.3 ohm respectively.
Relative error for parallel combination of resistors is
= dR/R²
= dR1/R1² + dR2/R2²
= 0.5/(24)² + 0.3/(8)²
= 0.5/ 24*24 + 0.3/ 64
= 0.5/576+0.3/ 64
= 32 + 172.8/ 36,864
=204.8/ 36,864=0.0055
=0.006
Percentage error =Relative error *100
= 0.006* 100 = 0.6