Question

What is the value of work done on an object when a 0.1x102–newton force moves it 30 meters and the angle between the force and the displacement is 25°?
A) 2.7 × 102 joules

B) 3.0 × 102 joules

C) 7.5 × 102 joules

D) 0 joules

Answer 1

Answer:

A) 2.7 × 102 joules

Explanation:

The work done by a constant force is given by:

$W=Fd cos \theta$

where

F is the magnitude of the force

d is the distance over which the force is applied

$\theta$ is the angle between the direction of the force and the displacement

In this problem, we have:

$F=0.1 \cdot 10^2 N$

d=30 m

$\theta=25^{\circ}$

Substituting into the equation, we find the work done

$W=Fd cos \theta=(0.1 \cdot 10^2 N)(30 m)(cos 25^{\circ})=271 J=2.7 \cdot 10^2 J$

Answer 2

The Answer to the question above is A. 2.7 x 102 joules.