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timama [110]
2 years ago
10

What keeps an inflated balloon from falling down if you rub it against your hair and place it against a wall? 1. rubbing distort

s the atoms inside the ballon and polarizes it. 2. rubbing leaves a balloon electrically charged; the charged balloon polarizes the wall. 3. when you rub the balloon against your hair, it will remove some m?
Physics
1 answer:
Keith_Richards [23]2 years ago
3 0
2 because when you are doing this it causes friction Which then cause the balloon to stick
~dany-ley
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The eyes of many older people have lost the ability to accommodate, and so an older person’s near point may be more than 25 cm f
tensa zangetsu [6.8K]

Answer:

Smaller refractive power

Explanation:

The refractive power of an eye is the extent to which it can converge or diverge the light rays.

Near point is the the closest point for an eye such that when an object is placed at that point the image it forms is sharp and clearly visible to the eye.

A the person ages, the ciliary muscles of the eyes weakens and as a result the lens contracts and the formation of the image takes place behind the retina instead of forming at the retina.

Thus the near point also increases and the refractive power becomes smaller.

4 0
1 year ago
A coworker did not clean his work area before going home this could cause an accident so you quickly clean up the next day you s
defon

Answer:

THE FIRST ONE YOU SHOULD TELL HIM AND THE LAST ONE YOU SHOUDENT DO BECAUSE HE WILL DO IT AGAIN AND EXPECT OTHERS TO CLEAN UP AFTER HIM

Explanation:

5 0
1 year ago
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A projectile follows a straight-line path instead of a parabolic trajectory. Which could be the launch angle? would it be 90 or
Gnesinka [82]
<em>projectile can only follow the straight line path when it is launched upward straightly so the correct option is <u>90 degree with respect to horizontal x -axis ..:)</u></em>
7 0
1 year ago
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Nora tied a string around a tennis ball, and then she swung it in a circle in front of her to demonstrate a planet orbiting the
777dan777 [17]

<em>Choice-A </em>is a true statement. The string holding the ball in orbit is a contact force, whereas gravity is a non-contact force.

Choice-C is half-true.  The string keeps the distance between the bodies constant, but gravity doesn't "MAKE" the distance vary.

8 0
1 year ago
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Two flat conductors are placed with their inner faces separated by 6.0 mm. If the surface charge density on one of the inner fac
dangina [55]

Explanation:

Relation between electric field and charge density is as follows.

           E = \frac{\sigma}{2 \epsilon}

where,    \sigma = charge density

              \epsilon = permittivity of free space = 8.85 \times 10^{-12}

So,  E_{\text{outside}} = 0

      E_{inside} = \frac{+\sigma}{2 \epsilon} - \frac{-\sigma}{2 \epsilon}

or,     E_{inside} = \frac{\sigma}{\epsilon}

Now, formula to calculate the potential difference of two conductors is as follows.

         V_{1} - V_{2} = \frac{\sigma \times d}{\epsilon}

It is given that,

           d = 6.0 mm = 6 \times 10^{-3} m

        \sigma = 40 \times 10^{-12} C/m^{2}

Hence, we will calculate the magnitude of the electric potential differences between the two conductors as follows.

        V_{1} - V_{2} = \frac{\sigma \times d}{\epsilon}

                     = \frac{40 \times 10^{-12} \times 6 \times 10^{-3}}{8.85 \times 10^{-12}}      

                     = 0.0271 volts

thus, we can conclude that value of the magnitude of the electric potential differences between the two conductors is 0.0271 volts.

7 0
2 years ago
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