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Goshia [24]
2 years ago
3

Find the frequency of light f radiated by an electron moving from orbit n1=2 to n2=1 inside of a he+ ion. express your answer in

hertz to three significant figures.
Physics
1 answer:
kumpel [21]2 years ago
7 0
According to the Bohr model of a hydrogen atom, the frequency of light radiated by an electron moving from an orbit n₁ to an orbit n₂ corresponds to the energy level difference between n₁ and n₂<span> of :
                                                               E = E</span>₀ (1/n₁² -1/n₂²)
Where,
            E₀ = mₓZ²e⁴/32
π²∈₀h²

Where,
mₓ is the electron mass
Z is the atomic number
e is the magnitude of the electron charge
∈₀ is the permittivity of free space
h  is Planck's constant divided by 2π.

In the case of hydrogen (Z = 1).
∈₀ = -13.6 eV

The frequency of light f radiated by an electron = 9.860×10¹⁵ Hz
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A hydroelectric dam holds back a lake of surface area 3.0×106m2 that has vertical sides below the water level. The water level i
Ber [7]

Answer:

4.41 × 10¹² J, 2.72 × 10³ m³, 0.907 × 10 ⁻³ m

Explanation:

Gravitational potential energy = mgh

where m is mass in kg, g is acceleration due to gravity in m/s², and h is the distance from the base of the dam.

mass of the surface water = density of water × volume of water × 1 m = 1000 kg / m³ × 3.0 × 10⁶ m² × 1 m = 3 × 10⁹ kg

Gravitational potential energy = 3 × 10⁹ kg × 9.81 m/s² × 150 m = 4.41 × 10¹² J

b)what volume of water must pass through the dam to produce 1000 kw-hrs

1 000 kw-hr = 3.6 × 10 ⁹ J

the dam has mechanical energy conversion of 90% to electrical energy

Gravitational potential energy needed = 3.6 × 10 ⁹ J / 0.9 = 4 × 10⁹ J

mass of water needed = Energy  required / g h =  4 × 10⁹ J / (9.81 m/s² × 150 m) = 2.718 × 10 ⁶ kg

density = mass / volume

volume = mass / density =  2.718 × 10 ⁶ kg / (1000 kg/ m³) = 2.72 × 10³ m³

the distance the level of  the water in the lake fell = volume / area =  2.72 × 10³ m³ / (3.0×10⁶ m²) = 0.907 × 10 ⁻³ m

8 0
2 years ago
A professor's office door is 0.89 m wide, 2.0 m high, and 4.0 cm thick; has a mass of 25 kg ; and pivots on frictionless hinges.
taurus [48]
In order to answer this question ... strange as it may seem ...
we only need one of those measurements that you gave us
that describe the door.

The door is hanging on frictionless hinges, and there's a torque
being applied to it that's trying to close it.  All we need to do is apply
an equal torque in the opposite direction, and the door doesn't move.

Obviously, in order for our force to have the most effect, we want
to hold the door at the outer edge, farthest from the hinges.  That
distance from the hinges is the width of the door ... 0.89 m.

We need to come up with 4.9 N-m of torque,
applied against the mechanical door-closer.

Torque is (force) x (distance from the hinge).

                                    4.9 N-m  =  (force) x (0.89 m) 

Divide each side by 0.89m:    Force = (4.9 N-m) / (0.89 m)

                                                             =  5.506 N .
7 0
2 years ago
A standard baseball has a circumference of approximately 23 cm . if a baseball had the same mass per unit volume as a neutron or
Svetlanka [38]

<u>Answer:</u>

 Mass of base ball  m_b=3.992*10^{14}kg  

<u>Explanation:</u>

  Circumference of baseball = 2πr = 23 cm

  So radius of baseball = 3.66 cm = 3.66*10^{-2} m

   Mass per unit volume of baseball = Mass per unit volume of neutron or proton.

   Mass of proton = 10^{-27} kg  

   Diameter of proton = 10^{-15} m

   Radius of proton =  5*10^{-16} m

   Volume of ball = \frac{4}{3} \pi r^3

   Now substituting all values in Mass per unit volume of baseball = Mass per unit volume of neutron or proton.    

         \frac{m_b}{\frac{4}{3}\pi *(3.66*10^{-2})^3} =\frac{10^{-27}}{\frac{4}{3}\pi *(5*10^{-16})^3}

         \frac{m_b}{(3.66*10^{-2})^3} =\frac{10^{-27}}{(5*10^{-16})^3}  

         m_b=3.992*10^{14}kg

       So mass of base ball  m_b=3.992*10^{14}kg              

5 0
2 years ago
Read 2 more answers
Buffalo, New York, experienced a snowstorm November 13–21, 2014. Residents refer to the event as “Snowvember.” What was the like
scZoUnD [109]
I know you're probably done with this by now, but the answer is *Lake-Effect Snow*
5 0
2 years ago
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If the mass of a material is 45 grams and the volume of the material is 8 cm^3, what would the density of the material be?
Svet_ta [14]
The density of the substance is the ratio of its mass over the space it occupies. In mathematical equation, this can be expressed as,

        ρ = m / v

where ρ is density, m is mass, and v is volume. 

Substituting the known values from the given,
 
    ρ = (45 g) / (8 cm³)

     ρ = 5.625 g/cm³

<em>ANSWER: 5.625 g/cm³</em>
3 0
2 years ago
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