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SCORPION-xisa [38]
2 years ago
9

Safe practices that Gene should observe are listed below. Place the numbers 1 through 4 next to the steps below to indicate the

proper order in which Gene should carry out the steps.
Use heat-resistant gloves or tongs to swirl the flask.

Put on safety goggles and an apron.

Check the flask for chips and cracks.

Read the entire lab procedure through and make sure it is understandable.
Chemistry
2 answers:
Dmitry [639]2 years ago
7 0
1, Read the entire lab procedure through and make sure it is understandable.   2, Put on safety goggles and an apron.  3, Check the flask for chips and cracks.   4, <span>  Use heat-resistant gloves or tongs to swirl the flask.</span>
Nataly [62]2 years ago
6 0

Explanation:

While performing in a laboratory, it is advisable to go through the instructions listed or told by your mentor so that any kind of mishappening.

Also, we should wear lab coat and safety gloves to avoid any kind of chemical contact with our skin. Tongs must be used while heating a test tube or flask.

Therefore, proper order of steps that should be followed by Gene are as follows.

1). Read the entire lab procedure through and make sure it is understandable.

2). Put on safety goggles and an apron.

3). Check the flask for chips and cracks.

4). Use heat-resistant gloves or tongs to swirl the flask.

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When 50 ml (50 g) of 1.00 m hcl at 22oc is added to 50 ml (50 g) of 1.00 m naoh at 22oc in a coffee cup calorimeter, the tempera
vitfil [10]

Answer:

\boxed{\text{2700 J}}

Explanation:

HCl + NaOH ⟶ NaCl + H₂O

There are two energy flows in this reaction.  

Heat of reaction + heat to warm water = 0  

           q₁             +              q₂                 = 0  

           q₁             +          mCΔT              = 0  

Data:

    m(HCl) = 50 g

m(NaOH) = 50 g

           T₁ = 22       °C

          T₂ = 28.87 °C

           C = 4.18 J·°C⁻¹g⁻¹

Calculations:

 m = 50 + 50 = 100 g

ΔT = 28.87 – 22 = 6.9 °C

 q₂ = 100 × 4.18 × 6.9 = 2900 J

q₁ + 2900 = 0

q₁ = -2900 J

The negative sign tells us that the reaction produced heat.

The reaction produced \boxed{\textbf{2900 J}}.

7 0
2 years ago
A 0.2-mm-thick wafer of silicon is treated so that a uniform concentration gradient of antimony is produced. One surface contain
krek1111 [17]

Answer:

- 0.0249% Sb/cm

-1.2465 * 10^9 \frac{atoms}{cm^3.cm}

Explanation:

Given that:

One surface contains 1 Sb atom per  10⁸  Si atoms and the other surface contains 500 Sb atoms per  10⁸ Si atoms.

The concentration gradient in atomic percent (%) Sb  per cm can be calculated as follows:

The difference in concentration = \delta_c

The distance \delta_x = 0.2-mm = 0.02 cm

Now, the concentration of silicon at one surface containing  1 Sb atom per 10⁸ silicon atoms and at the outer surface that has 500 Sb atom per   10⁸ silicon atoms can be calculated as follows:

\frac{\delta_c}{\delta_c} = \frac{(1/10^8 -500/10^8)}{0.02cm} *100%

= - 0.0249% Sb/cm

b) The concentration (c_1) of Sb in atom/cm³ for the surface of 1 Sb atoms can be calculated by using the formula:

c_1 = \frac{(8 si atoms/unit cells)(1/10^3)}{(lattice parameter)^3/unit cell}

Lattice parameter = 5.4307 Å;  To cm ; we have

= 5.4307A^0* \frac{10^{-8}cm}{ A^0}

c_1 = \frac{(8 si atoms/unit cells)(1/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}

= 0.00499*10^{17}atoms/cm^3

The concentration (c_2) of Sb in atom/cm³ for the surface of 500 Sb can be calculated as follows:

c_1 = \frac{(8 si atoms/unit cells)(500/10^8)}{(5.4307*10^{-8}cm)^3/unit cell}

   =  \frac{4*10^{-3}}{1.601*10^{-22}}

   = 2.4938*10^{17}atoms/cm^3

Finally, to calculate the concentration gradient

(\frac{\delta _c}{\delta_ x}) = \frac{c_1-c_2}{\delta_x}

(\frac{\delta _c}{\delta_ x}) = \frac{0.00499*10^{17}-2.493*10^{17}}{0.02}

= -1.2465 * 10^9 \frac{atoms}{cm^3.cm}

8 0
2 years ago
For which of the following reactions is ΔH∘rxn equal to ΔH∘f of the product(s)?You do not need to look up any values to answer t
Nutka1998 [239]

Answer:

Reactions 1, 3 and 5

Explanation:

First thing's first, let's ensure that all the reactions given are balanced. This is given as;

CO(g) + 1/2 O2(g )→ CO2(g)

Li(s) + 1/2 F2(l) → LiF(s)

C(s) + O2(g) → CO2(g)

CaCO3(g) → CaO + CO2(g)

2Li(s) + F2(g) → 2LiF(s)

For the condition to be valid;

- There is by convention 1 mol of product made. This means we eliminate reactions with more than one mole of compound formed. This eliminates reaction 5.

- The lements haveto be in their state at room temperature. Fluorine is a gas, not a liquid, at room temperature ans pressure, so 2 is not a correct answer.

This leaves us with reactions 1, 3 and 5 as the correct reactions that satisify the condition.

3 0
2 years ago
The plastic straws were placed under the wooden block to
Sveta_85 [38]
Answer: C
I hope this helped you
6 0
2 years ago
When exposed to very high temperatures, metals like iron can be turned into fluids that flow and can be poured into molds. What
oksano4ka [1.4K]

Answer: B) The energy of the solid increases, and the particles begin to slide past each other.

Explanation:

The energy of the solid matter is required to be increased so that molecules of the solid matter get separated from each other and an transition from solid matter to liquid matter occurs. The liquid components of the matter will slide past each other as they have obtain energy for fluidity. The liquid iron can be molded into any shape and the energy decreases considerably.

7 0
2 years ago
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