A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l
2 answers:
You might be interested in
Answer:
a) the mug hits the floor 0.7425m away from the end of the bar. b) |V|=5.08m/s θ= -72.82°
Explanation:
In order to solve this problem, we must first start by doing a drawing of the situation. (see attached picture).
a)
From the drawing we can see that we are dealing with a two dimensions movement problem. So in order to find out how far away from the bar the mug will fall, we need to start by finding how long it will take the mug to be in the air, so we analyze the vertical movement of the mug.
In order to find the time we need to use the following formula, which contains the data we know:
we know that and that
as well, so the formula is simplified to:
we can now solve this for t, so we get:
we know that and that
the acceleration of gravity is negative because the mug is moving downwards. So we substitute them into the given formula:
which yields:
t=0.495s
we can now use this to find the horizontal distance the mug travels. We know that:
so we can solve this for x, so we get:
and we can now substitute the values we know:
x=(1.5m/s)(0.495s)
which yields:
x=0.7425m
b) Now that we know the time it takes the mug to hit the floor, we can use it to find the final velocity in the y-direction by using the following formula:
we know the initial velocity in the vertical direction is zero, so we can simplify the formula:
so we can solve this for the final velocity:
in this case the acceleration is the same as the acceleration of gravity (which is negative) so we can substitute that and the time we found on the previous part to get:
which yields:
so now we know the components of the final velocity, which are:
and
so now we can find the speed by determining the magnitude of the vector, like this:
so we get:
which yields:
|V|=5.08m/s
now, to find the direction of the impact, we can use the following equation:
so we get:
which yields:
Answer:
Explanation:
Given
radius of wheel
mass of wheel
Force
Moment of Inertia of solid wheel
Torque is given by
Force on the axle is 32 N since there is no linear acceleration of the system
using Third law F=32 N
Torque of the axle applied to the wheel is zero because force of axle imparted at the center of axle