Answer: The temperature rise is 
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
Q = Heat absorbed by ice = 5280 J
m = mass of ice = 2.40 kg = 2400 g (1kg=1000g)
c = heat capacity of water = 
Initial temperature = 
Final temperature = 
Change in temperature ,
Putting in the values, we get:
Thus the temperature rise is
Answer:
748 torr
Explanation:
mmHg and torr are equivalent so, you'll have 748 torr.
Remember that density refers to the "mass per unit volume" of an object.
So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.
In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is
As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:
density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml
The effect on density would be that it would erroneously appear to be greater
Hope this helps!
Good luck
Cookware manufacturers who make pans out of steel only because if C-8 is discontinued then people would have no choice but to buy steel pans. The steel pan manufacturers would in return receive a lot of money
1. I think you chose the right answer, the equation has the states of the reactants and products.
2. I think you chose the right answer.
3. I think you also chose the right answer. Assuming that the Hrxn is written as kJ per mol CH4
4. Heat of solution is the enthalpy change associated with dissolving a solute in a solvent. I think the first choice is the right one.
5. I think you chose the right answer.
