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Colt1911 [192]
2 years ago
12

Which compound(s) contain the most hydrogen atoms per molecule or formula unit? hydrogen selenide ammonium bromide strontium dih

ydrogen phosphate sodium bicarbonate?
Chemistry
1 answer:
igomit [66]2 years ago
3 0

The answer is strontium dihydrogen phosphate

That is strontium dihydrogen phosphate, is the compound containing the most hydrogen atoms per molecule or formula unit.

The formulas of the following compounds are as follows:

Hydrogen selenide H₂Se

Ammonium bromide NH₃Br  

Strontium dihydrogen phosphate  Sr(H₂PO4)₂

Sodium bicarbonate  NaHCO₃

As it can be seen from the formula of strontium dihydrogen phosphate  Sr(H₂PO4)₂ , that it contains the most hydrogen atoms per molecule or formula unit.


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(a) calculate the %ic of the interatomic bond for the intermetallic compound tial3. (b) on the basis of this result, what type o
Mrrafil [7]

Answer :

The correct answer is  %IC = 10 % and bond is  covalent  bond with slight polarity.

<u>Percent Ionic Character :</u>

It is defined as percent of ionic character present in a  polar covalent bond . The formula   of % ionic character (%IC) is given as follows :

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^X^a^-^X^b^) * 100

Where Xa = Electronegativity of A atom   and Xb = Electronegativity of B atom

Given : Molecule is TiAl₃

Electronegativity of Ti = 2.0

Electronegativity of Al = 1.6 ( From image shared )

Plug the value  in  above formula :

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^2^.^0^-^1^.^6^) * 100

Percent Ionic character = 1 - e^(^-^0^.^2^5 ^*^0^.^4^) * 100

Percent Ionic character = 1 - e^(^-^0^.^1^) * 100

Value of e⁻¹ = 0.90

Percent ionic character = 1 - 0.90 * 100

Percent Ionic character = 10 %

<u>Since the % IC is 10 % , which is very less comparatively , hence the bond is covalent and  very less polar .</u>

8 0
2 years ago
How much 2 M HBr is needed to neutralize 380 mL of 0.1 M NH4OH?
Nata [24]

Answer:

19ml

Explanation:

trust me

8 0
2 years ago
After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
FromTheMoon [43]

Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

0,28g × (1mol / 14,006g) = 0,02 moles of N

Dividing each value in 0,01 to obtain natural numbers:

0,03 moles of Mg / 0,01 = 3

0,02 moles of N / 0,01 = 2.

Thus, empirical formula is: <em>Mg₃N₂</em>

<em></em>

I hope it helps!

5 0
2 years ago
Give two areas where the compressible nature of gas is applied​
galina1969 [7]

Answer:

1. Gases can be easily liquefied into very small volumes and stored in liquid form Eg in LPGA cylinders and used in homes.

2. Balloons can be easily filled with air.

6 0
1 year ago
How and why do ionic bonds form? Check all of the boxes that apply. Ionic bonds form between metal atoms and other metal atoms.
sammy [17]

2 Ionic bonds form between metal atoms and nonmetal atoms.

4 The less electronegative atoms transfers one or more electrons to the more electronegative atom.

5 The metal atom forms a cation and the nonmetal atom forms an anion.

7 The attraction between ions with an opposite charge forms an ionic bond.



8 0
2 years ago
Read 2 more answers
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