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Alekssandra [29.7K]
1 year ago
8

CCl, 189.86 g/mol. Express your answer as a chemical formula.

Chemistry
1 answer:
kompoz [17]1 year ago
5 0

Answer is: a chemical formula of the compound is C₄Cl₄.

CCl is empirical formula of the compound. Empirical formula gives the proportions of the elements present in a compound, so we know that proportion od carbon and chlorine is 1 : 1 (n(C) : n(Cl) = 1 : 1).

M(CCl) = Ar(C) + Ar(Cl) · g/mol.

M(CCl) = 12.0107 + 35.453 · g/mol.

M(CCl) = 47.4637 g/mol; molar mass of empirical formula.

M(compound) = 189.86 g/mol; molar mass of the compound.

M(compound) / M(CCl) = 189.86 g/mol / 47.4637 g/mol.

M(compound) / M(CCl) = 4; chemical formula of the compound have four carbon and four chlorine atoms.

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Answer:

  • 820 K

Explanation:

As per Boltzman equation, <em>kinetic energy (KE)</em> is in direct relation to the <em>temperature</em>, measured in absolute scale Kelvin.

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Then, <em>the temperature at which the molecules of an ideal gas have 3 times the kinetic energy they have at any given temperature will be </em><em>3 times</em><em> such temperature.</em>

So, you must just convert the given temperature, 32°F, to kelvin scale.

You can do that in two stages.

  • First, convert 32°F to °C. Since, 32°F is the freezing temperature of water, you may remember that is 0°C. You can also use the conversion formula: T (°C) = [T (°F) - 32] / 1.80

  • Second, convert 0°C to kelvin:

         T (K) = T(°C) + 273.15 K= 273.15 K

Then, <u>3 times</u> gives you: 3 × 273.15 K = 819.45 K

Since, 32°F has two significant figures, you must report your answer with the same number of significan figures. That is 820 K.

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Also, we need to understand that when the  Neutron- Proton ratio is LESS THAN 1 or GREATER THYAN 1.5, then we say the nuclei is UNSTABLE.

So, let us check which is stable and which is unstable:

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b. 7 protons and 7 neutrons  =  Neutron- proton ratio = N/P = 7/7= 1 = stable.

c. 2 protons and 3 neutrons  =  Neutron- proton ratio = N/P = 3/5 =0.6 =unstable.

d. 3 protons and 0 neutrons  =  Neutron- proton ratio = N/P = 0/3= 0= unstable.

e. 6 protons and 5 neutrons  =  Neutron- proton ratio = N/P = 5/6= 0.83 = unstable.

f. 9 protons and 9 neutrons  =  Neutron- proton ratio = N/P = 9/9 = 1 = stable.

g. 8 protons and 7 neutrons  =  Neutron- proton ratio = N/P =  7/8 =0.875 = unstable.

h. 1 proton and 0 neutrons =  Neutron- proton ratio = N/P = 0/1 =0 = unstable

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8 molecules of O2 are required.
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