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aliina [53]
2 years ago
9

In triangle XYZ, if angle X is congruent to angle Z, XY = 13x - 21, YZ = 8x - 6, & XZ = x + 4, find x & the measure of e

ach angle.

Mathematics
1 answer:
Naily [24]2 years ago
8 0

Answer:

Given: In triangle XYZ, \angle X \cong \angle Z , XY=13x-21 , YZ=8x-6 and XZ=x+4.

If two angles are congruent if and only if, they measure the same  number of degrees.

therefore, from the given condition;  \angle X = \angle Z.

Isosceles Triangle : An triangle with two equal sides. The angles opposite the equal sides are also equal.

Therefore, the triangle XYZ is an isosceles triangle, as the base angle \angle X and \angle Z are equal and the sides opposite to these angles are also equal i.e,  XY=YZ.

Since, we have XY=YZ ,

⇒ 13x-21 =8x-6 or

13x-8x=21-6   or

5x=15

Simplify:

x=3

Therefore, the sides of an isosceles triangle are:

XY = 13x-21 = 13\cdot 3 -21 = 39-21 = 18 unit ,

YZ = 8x-6 = 8 \cdot3 -4 = 24-6 =18 unit,

and XZ = x+4 = 3+4 =7 unit.

Since, the triangle is isosceles, we draw a line from an vertex angle Y of a triangle XYZ which is perpendicular (i.e, of 90 degree angle) to opposite side meets the opposite side at its midpoint i.e, say W.

As W is the midpoint(i.e, it divide the sides into two equal halves),

XW=WZ = \frac{7}{2} =3.5 unit

Now, use the Pythagorean theorem, to find the altitude WY.

⇒ (WY)^2+(WZ)^2=(YZ)^2

Substitute the value of WZ = 3.5 unit and YZ = 18 unit in above formula to calculate the length of WY;

⇒ (WY)^2+(3.5)^2=(18)^2

Simplify:

(WY)^2=324-12.25=311.75 or

WY=\sqrt{311.75}

On simplify we get;

WY=17.65 unit(approx.)

The vertex angle Y is split into two equal angles, we can find the vertex angle by finding the one of the base angle by using the fact; Cosine = \frac{Base}{Hypotenuse}.

⇒ \cos Z =\frac{3.5}{18}

⇒ \cos Z = 0.195(approx) or  

Z=\cos^{-1}(0.195)

Therefore, the angle \angle Z = 78.7^{\circ}.

The sum of the measure of the angle in the triangle is 180 degree.

In triangle XYZ.

\angle X +\angle Y+\angle Z =180^{\circ}

Since \angle X=\angle Z =78.7^{\circ}

then,

78.7^{\circ}+\angle Y+78.7^{\circ}=180^{\circ}

⇒157.4^{\circ}+\angle Y=180^{\circ}

Simplify:

\angle Y=22.6^{\circ}.

Therefore, the measure of each angle are: \angle X=\angle Z=78.7^{\circ} and \angle Y =22.6^{\circ}











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Answer:

Step-by-step explanation:

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p = (1-0.02)^9 * 0.02 = 0.98^9 * 0.02 = 0.01666

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Ben swims​ 50,000 yards per week in his practices. Given this amount of​ training, he will swim the​ 100-yard butterfly in 51.5
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Answer:

MArginal productivity: \frac{dt}{dL}=-0.0002

We can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

Step-by-step explanation:

The marginal productivy is the instant rate of change in the result for an increase in one unit of a factor.

In this case, the productivity is the time he last in the 100-yard. The factor is the amount of yards he train per week.

The marginal productivity can be expressed as:

\frac{dt}{dL}

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We can not derive the function because it is not defined, but we can approximate with the last two points given:

\frac{dt}{dL}\approx\frac{\Delta t}{\Delta L} =\frac{t_2-t_1}{L_2-L_1}=\frac{44.6-46.4}{70,000-60,000}=\frac{-2.0}{10,000}=-0.0002

Then we can interpret this as he will reduce his time an <em>additional </em>0.0002 seconds for every <em>additional </em>yard he trains.

This is an approximation that is valid in the interval of 60,000 to  70,000 yards of training.

6 0
1 year ago
A production line operates with a mean filling weight of 16 ounces per container. Overfilling or underfilling presents a serious
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Answer:

Part1) z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

p_v =2*P(Z>2.191)=0.0284

Readjustment is needed

Part 2)  z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

p_v =2*P(Z

No readjustment is needed

Step-by-step explanation:

Data given and notation

Part 1    

\bar X=16.32 represent the sample mean    

\sigma=0.8 represent the population standard deviation    

n=30 sample size    

\mu_o =16 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a two tailed test.    

What are H0 and Ha for this study?    

Null hypothesis:  \mu =16    

Alternative hypothesis :\mu \neq 16    

Compute the test statistic  

The statistic for this case is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{16.32-16}{\frac{0.8}{\sqrt{30}}}=2.191    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z>2.191)=0.0284

Using the value of \alpha =0.05 we see that pv and we have enough evidence to reject the null hypothesis.

Readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)    

Part 2

\bar X=15.82 represent the sample mean    

We can replace in formula (1) the info given like this:    

z=\frac{15.82-16}{\frac{0.8}{\sqrt{30}}}=-1.232    

Give the appropriate conclusion for the test  

Since is a two tailed test the p value would be:    

p_v =2*P(Z

Using the value of \alpha =0.05 we see that pv>\alpha and we have enough evidence to FAIL to reject the null hypothesis.

No readjustment is needed

The rejection zone is given by:

(-\infty ;-1.96) , (1.96;\infty)  

What action would you recommend ?

Review the procedure.

Do you reach the same conclusion ?

No we got different conclusions

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I would add 7 to get ...

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then divide by 2 to get

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The root can be simplified, so we have ...

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The above method seemed the most obvious method to me. One could use the quadratic formula, but that seems to involve more operations.

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7 0
2 years ago
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BlackZzzverrR [31]

Answer:

c.33.08

Step-by-step explanation:

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