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1 year ago

Burning a piece of wood in fire can be best described as a

2 answers:

6 0

Burning a piece of wood in fire can best be described as a CHEMICAL CHANGE BECAUSE THE ATOMS IN WOOD AND OXYGEN ARE REARRANGED.

In chemistry, there are two types of change, these are chemical and physical changes. In physical change, no new substance is formed and the process is usually reversible. In chemical change, chemical reactions usually occur, new substances are formed and the process is not reversible. Burning of wood in air is a chemical change because the atoms of the wood and the oxygen atoms react together to form new substances and the reaction is not reversible.

pishuonlain [190]1 year ago

4 0

Burning a piece of wood in fire can be best described as a chemical change.

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What pressure (in atm) would be exerted by 76 g of fluorine gas (f2) in a 1.50 liter vessel at -37oc? (a) 26 atm(b) 4.1 atm(c) 1

nirvana33 [79]

Let's assume that the F₂ gas has ideal gas behavior.

Then we can use ideal gas formula,
PV = nRT

Where, P is the pressure of the gas (Pa), V is the volume of the gas (m³), n is the number of moles of gas (mol), R is the universal gas constant ( 8.314 J mol⁻¹ K⁻¹) and T is temperature in Kelvin.

Moles = mass / molar mass

Molar mass of F₂ = 38 g/mol

Mass of F₂ = 76 g

Hence, moles of F₂ = 76 g / 38 g/mol = 2 mol

P = ?
V = 1.5 L = 1.5 x 10⁻³ m³

n = 2 mol

R = 8.314 J mol⁻¹ K⁻¹
T = -37 °C = 236 K

By substitution,

P x 1.5 x 10⁻³ m³ = 2 mol x 8.314 J mol⁻¹ K⁻¹ x 236 K

p = 2616138.67 Pa

p = 25.8 atm = 26 atm

Hence, the pressure of the gas is 26 atm.

Answer is "a".

5 0

1 year ago

Use the PhET simulation to identify what happens to the concentrations of a dilute Drink mix mixture or a pure Drink mix solutio

elena-s [515]

Hello user, you did not add a picture of an attachment to enable me help you solve this problem. Please check the attachment I added i believe it is the question that needs to be solved.

Explanation:

1. In the first column

INCREASE CONCENTRATION: these are the items that needs to be placed in this bin

a. Add drink mix solid to a diluted mixture of drink mix in pure water

b. Add drink mix solution to a diluted mixture of drink mix in pure water

c. Add drink mix solid to pure drink mix solution

d Evaporate water from a diluted mixture of drink mix in pure water

e Evaporate water from pure drink mix solution

2. The items below are what should be placed in this bin,DECREASE CONCENTRATION:

a. Add water to a diluted mixture of drink mix in pure water

b. Add water to pure drink mix solution

3. These items here should be placed here. DOES NOT AFFECT CONCENTRATION:

a. Add pure drink mix solution to pure drink mix solution

b. Drain the pure drink mix solution

c. Drain the diluted mixture

7 0

2 years ago

The ksp of agcl is 1.6 x 10-10. what is the solubility of agcl in 0.010 m fecl3? give your answer using scientific notation (1.2

bija089 [108]

Ksp of AgCl= 1.6×10⁻¹⁰

AgCl=Ag⁺ +Cl⁻

Ksp=[Ag⁺][Cl⁻]

Assume [Ag⁺]=[Cl⁻]=x

Ksp=x²

1.6×10⁻¹⁰=x²

x=0.000012

In FeCl₃:

FeCl₃------>Fe⁺³+ 3Cl⁻

as there is 0.010 M FeCl₃

So there will be ,

[Cl⁻]= 0.030

[Ag⁺]=Ksp/[Cl⁻]

=1.6×10⁻¹⁰/0.030

=5.3×10⁻⁹

so solubility of AgCl in FeCl₃ will be 5.3×10⁻⁹.

7 0

2 years ago

Read 2 more answers

Complete the sentence. When an acid is added to water, hydroxide ions __________.

kenny6666 [7]

Answer:

The hydroxide ions decrease.

Explanation:

I got it right on the quiz. This is what I saw. Read this, "Adding water to an acid or base will change its pH. Water is mostly water molecules so adding water to an acid or base reduces the concentration of ions in the solution. When an acidic solution is diluted with water the concentration of H + ions decreases and the pH of the solution increases towards 7."

Hope this helps! Tell me if this is wrong just incase.

8 0

2 years ago

Read 2 more answers

Determine the mass in grams of 3.00 × 10²¹ atoms of arsenic. (The mass of one mole of arsenic is 74.92 g.)

Tpy6a [65]

Answer:

The answer to your question is: 0.373 g

Explanation:

Data

mass = ? g

atoms = 3 x 10 ²¹

AM = 74.92 g

Process

1 mol of As ------------------ 6.023 x 10²³ atoms

x ------------------ 3 x 10 ²¹ atoms

x = 4.98 x 10⁻³ moles

1 mol ------------------------ 74.92 g

4.98 x 10⁻³ moles------- x

x = (4.98 x 10⁻³ x 74.92)/1

x = 0.373 g of As

3 0

2 years ago