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vlada-n [284]
2 years ago
5

Compare how entropy changes for the following two systems: System A: A gas and a solid react to form a new solid product. System

B: Rubbing alcohol evaporates on the skin.
Chemistry
1 answer:
abruzzese [7]2 years ago
5 0

Answer:

In system A: A gas and a solid react to form a new solid product. the system entropy decreases.

In System B: Rubbing alcohol evaporates on the skin. liquid alcohol is converting to gas by evaporation so the system entropy increases.

Explanation:

Entropy  is a thermodynamic quantity measure the degree of disorder of a certain system.

Gases have larger entropy compared to liquids  which is larger than solids.

================================================================

(A) When a gas convert to a solid, its entropy decreases. ... because solids have less energy and entropy than solids.

So, in system A: A gas and a solid react to form a new solid product. the system entropy decreases.

================================================================

(B) Any chemical reaction that increases the number of gas molecules also increases entropy.

So, in System B: Rubbing alcohol evaporates on the skin. liquid alcohol is converting to gas by evaporation so the system entropy increases

================================================================

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When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a
AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

3 0
2 years ago
An electron is on a -2.5 eV energy level. The electron is struck by a 2.5 eV photon. What will most likely happen?
kati45 [8]
The correct answer would be C
5 0
2 years ago
Which electron has a higher probability of being found at 4 Å of the nucleus, one in a 2s orbital or one in a 2p orbital?
Lena [83]

Answer:

one in a 2s orbital

Explanation:

Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital

4 0
2 years ago
An empty beaker is weighed and found to weigh 23.1 g. Some potassium chloride is then added to the beaker and weighed again. The
GuDViN [60]

Answer:Mass of Potassium chloride =1.762g

Explanation:

Mass of empty beaker = 23.100 g

Mass of beaker with Potassium chloride = 24.862g

Mass of Potassium chloride = Final weight - initial weight = Mass of beaker with Potassium chloride  - Mass of empty beaker = 24.862-23.100 = 1.762g

8 0
2 years ago
Calculate the change in internal energy of the following system: a 100.0-g bar of gold is heated from 25 ∘C to 50 ∘C during whic
NikAS [45]
The Law states that the change in internal energy (U) of the system is equal to the sum of the heat supplied to the system (q) and the work done ON the system (W) 
<span>ΔU = q + W </span>

<span>For the first question, 0.653kJ of heat energy is removed from the system (balloon) while 386J of work is done ON the balloon, thus </span>
<span>ΔU = -653J + 386J </span>
<span>=-267J </span>
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<span>For the second question, 322J of heat energy is added to the system (gold bar) while no work is done on the gold bar, this is an isochoric/isovolumetric process, thus </span>
<span>ΔU = 322J + 0 </span>
<span>=322J </span>
<span>Thus internal energy increase by 322J</span>
8 0
2 years ago
Read 2 more answers
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