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olya-2409 [2.1K]

2 years ago

13

The SI units for measuring the velocity of the car: The SI units for measuring the acceleration of the car: The SI units for mea

suring force: The SI units for measuring mass:

2 answers:

Harlamova29_29 [7]2 years ago

4 0

Answer:

The SI unit of velocity, acceleration, force and mass of the car are m/s, m/s², kg-m/s² and kg.

Explanation:

SI unit is the international system units.

We need to define the SI unit of velocity, acceleration, force and mass of the car

The SI unit of velocity is

$v = m/s$

The SI unit of acceleration is

$a = m/s^2$

The SI unit of force is

$F = N=kg-m/s^2$

The SI unit of mass is

$m =kg$

Hence, The SI unit of velocity, acceleration, force and mass of the car are m/s, m/s², kg-m/s² and kg.

klasskru [66]2 years ago

3 0

Velocity ... m/s (meters per second) and angle

Acceleration ... m/s^2 and angle

Force ... Newton (kg-m/s^2) and angle

Mass ... kilogram

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A student practicing for a cross country meet runs 250 m in 30 s. What is the average speed

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Answer:8.3m/sec 30 sec,

Explanation:

A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.

5 0

1 year ago

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Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec

salantis [7]

Answer:

Value of angle between vector a and b is $56.30^{\circ}$ .

Explanation:

Vectors a and b have scalar product 6.00

Let $\theta$ be the angle between a and b.

$\vec{a}.\vec{b} = 6$

ab cos $\theta$ = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

$\vec{a} \times\vec{b} = 9$

ab sin $\theta$ = 9 ...(2)

Dividing equation (2) by (1) we get

$\frac{ab sin \theta}{ab cos \theta} = \frac{9}{6}$

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3 0

2 years ago

The drawing shows three identical springs hanging from the ceiling. Nothing is attached to the first spring, whereas a 4.50-N bl

Pavlova-9 [17]

Answer:

a. 30 N / m

b. 9.0 N

Explanation:

Given that

Unstretched length of the spring, $L_o$ = 20.0cm = 0.2m

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$L_1$ = 35.0cm = 0.35m

So, the change in spring length when mass hangs is

$x = L_1 - L_o$

= (0.35 - 0.20) m

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As spring are identical

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$k= \frac{4.50}{x} = \frac{4.50}{0.15}$

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$L_2$ = 50cm = 0.5m

So, the change in spring length is

$x'= L_2 - L_o$

= (0.5-0.20)m

= 0.30m

At equilibrium,

Restoring Force on spring = Block weightage

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$W'= kx'$

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4 0

2 years ago

A 96-mH solenoid inductor is wound on a form 0.80 m in length and 0.10 m in diameter. A coil is tightly wound around the solenoi

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Answer:

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