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tiny-mole [99]
2 years ago
13

A cardinal (Richmondena cardinalis) of mass 4.20×10−2 kg and a baseball of mass 0.146 kg have the same kinetic energy. What is t

he ratio of the cardinal's magnitude pc of momentum to the magnitude pb of the baseball's momentum?
Physics
1 answer:
bekas [8.4K]2 years ago
6 0

Explanation:

It is given that,

Mass of cardinal,m_c=4.2\times 10^{-2}\ kg

Mass of baseball, m_b=0.146\ kg

Both cardinal and baseball have same kinetic energy. We need to find the ratio of the cardinal's magnitude p_c of momentum to the magnitude p_c of the baseball's momentum.

E_c=E_b

Kinetic energy is given by, E=\dfrac{p^2}{2m}

\dfrac{p_c^2}{2m_c}=\dfrac{p_b^2}{2m_b}

(\dfrac{p_c}{p_b})^2=\dfrac{m_c}{m_b}

\dfrac{p_c}{p_b}=\sqrt{\dfrac{m_c}{m_b}}

\dfrac{p_c}{p_b}=\sqrt{\dfrac{4.2\times 10^{-2}}{0.146}}

So, \dfrac{p_c}{p_b}=\dfrac{53}{100}

So, the ratio of cardinal's magnitude of momentum to the magnitude of the baseball's momentum is 53 : 100

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Answer:

Mass, m = 2.2 kg                                

Explanation:

It is given that,

Frequency of the piano, f = 440 Hz

Length of the piano, L = 38.9 cm = 0.389 m

Tension in the spring, T = 667 N

The frequency in the spring is given by :

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

\mu=\dfrac{m}{L} is the linear mass density

On rearranging, we get the value of m as follows :

m=\dfrac{T}{4Lf^2}

m=\dfrac{667}{4\times 0.389\times (440)^2}

m = 0.0022 kg

or

m = 2.2 grams

So, the mass of the object is 2.2 grams. Hence, this is the required solution.

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A 29 cm pencil is placed 35cm in front of a convex lens and is illuminated by a spotlight. the focal point of the lens is 28cm f
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A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w
Aloiza [94]

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

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4 0
1 year ago
Ben starts walking along a path at 3 3 mi/h. One and a half hours after Ben leaves, his sister Amanda begins jogging along the s
Drupady [299]

Answer:

3 hours

Explanation:

Given:

- The speed of Ben v_b = 3 mi/h

- The speed of Amanda v_a = 6 mi/h

- The total time taken to cover distance(d) by ben = t_b

Find:

How long will it be before Amanda catches up to Ben?

Solution:

- The distance d traveled by Ben:

                                 d = v_b*t_b

                                 d = 3*t_b

- The distance d traveled by Amanda:

                                 d = v_a*t_a

                                 d = 6*t_a

- Equate the distance as when they meet:

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- Where ,

                                  t_b = t_a + 1.5

                                  t_a = t_b - 1.5

- Substitute the time relationship in distance relationship:

                                  3*t_b = 6*(t_b - 1.5)

                                  3*t_b = 6*1.5

                                      t_b = 2*1.5 = 3 h

- Hence, It would take 3 hours since Ben starts walking that amanda catches up.

4 0
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