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s2008m [1.1K]
2 years ago
12

Which circuits correctly show Ohm's law?

Physics
2 answers:
Elodia [21]2 years ago
6 0
Ohm’s Law:
V = IR
V = battery voltage, I = current, R = resistance

Top-left circuit:
V = 25V, I = 5A, R = 5ohm
25 = 5•5
25 = 25
This circuit is correct.

Top-right circuit:
V = 18V, I = 6A, R = 4ohm
18 = 6•4
18 =/= 24
This circuit is incorrect.

Bottom-left circuit:
V = 56V, I = 7A, R = 8ohm
56 = 7•8
56 = 56
This circuit is correct.

Bottom-right circuit:
V = 20V, I = 5A, R = 4ohm
20 = 5•4
20 = 20
This circuit is correct.

The following circuits are correct: top-left, bottom-left, and bottom-right.
Amiraneli [1.4K]2 years ago
5 0

Answer:

the top left and the bottom left and the bottom right

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B.

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A 6.0-cm-diameter, 11-cm-long cylinder contains 100 mg of oxygen (O2) at a pressure less than 1 atm. The cap on one end of the c
butalik [34]

Answer:

The temperature of the gas is 1197.02 K

Explanation:

From ideal gas law;

PV = nRT

Where;

P is the pressure of the gas

V is the volume of the gas

R is ideal gas constant = 8.314 L.kPa/mol.K

T is the temperature of the gas

n is the number of moles of gas

Volume of the gas in the cylindrical container = πr²h

Given;

r = 6/2 = 3 cm = 0.03 m

h = 11 cm = 0.11 m

V = π × (0.03)² × 0.11 = 3.11 × 10⁻⁴ m³ = 0.311 L

number of moles of oxygen gas = Reacting mass / molar mass

=\frac{0.1}{32} = 0.003125, moles

T = \frac{PV}{nR} = \frac{100X0.311}{0.003125X8.314} =1197.02K

Therefore, the temperature of the gas is 1197.02 K

6 0
2 years ago
In a power plant, pipes transporting superheated vapor are very common. Superheated vapor flows at a rate of 0.3 kg/s inside a p
grigory [225]

Answer:h=160.84 W/m^2-K

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

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specific heat of vapor(c)=2190 J/kg.k

heat supplied Q=mc\Delta T=0.3\times 2190\times (30)

Heat due to convection =hA(100-30)

A=\pi d\cdot L

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Q_{convection}=h\times 1.571\times (100-22)=122.538 h

Q=Q_{convection}

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Katarina [22]

Answer:

upward force acting = 261.6 N

Explanation:

given,

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arm length = 0.6 m

speed of the swing

net force must provide

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force of gravity = - mg

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7 0
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