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aleksley [76]
2 years ago
9

A solution is prepared by dissolving 0.60 g of nicotine (a nonelectrolyte) in water to make 12 mL of solution. The osmotic press

ure of the solution is 7.55 atm at 25 °C. The molecular weight of nicotine is __________ g/mol.
Chemistry
1 answer:
Mariulka [41]2 years ago
3 0

Answer:

Molecular weight of nicotine is 162 g/mol

Explanation:

Osmotic pressure (\pi) for nonelectrolyte is expressed as-

                                    \pi =CRT

where C is molarity of solution, R is gas constant and T is temperature in Kelvin scale.

If molecular weight of nicotine is W g/mol then number of moles of nicotine present in solution is equal to \frac{0.60}{W} moles

So, molarity (C) of solution = \frac{0.60\times 1000}{W\times 12}M

R is equal to 0.082 L.atm/(mol.K), T is 298 K and \pi) is 7.55 atm

So, 7.55=(\frac{0.60\times 1000}{W\times 12})\times (0.082)\times (298)

or, W = 162

So molecular weight of nicotine is 162 g/mol

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