Question

Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:

Answer 1

Answer : The number of silver atoms produced will be $39.66\times 10^{23}$

Explanation : Given,

Number of atoms of copper = $19.83\times 10^{23}$

The given balanced chemical reaction,

$Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag$

From the balanced chemical reaction we conclude that,

As, $6.02\times 10^{23}$ number of copper atoms react to give $2\times 6.02\times 10^{23}$ number of silver atoms.

So, $19.83\times 10^{23}$ number of copper atoms react to give $2\times \frac{6.02\times 10^{23}}{6.02\times 10^{23}}\times 19.83\times 10^{23}=39.66\times 10^{23}$ number of silver atoms.

Therefore, the number of silver atoms produced will be $39.66\times 10^{23}$