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Helen [10]
2 years ago
8

Which of the following reactions would be the most spontaneous at 298 K? Which of the following reactions would be the most spon

taneous at 298 ? A + B → 2C; E∘cell = -0.40 V A + B → C; E∘cell = +1.22 V A + 2B → C; E∘cell = +0.98 V A + B → 3C; E∘cell = +0.15 V More information is needed to determine.
Chemistry
1 answer:
mars1129 [50]2 years ago
4 0

Answer:

The most spontaneous is (B)

Explanation:

We follow the equation for Gibbs free energy:

\Delta G=-nFE_{cell}

Where n is the number of electrons involved, F is the Faraday's constant (96485 C/mol). As we do not know the number of electrons per reaction, we will assume the same number for every reaction for the sake of the comparison:

a) \frac{\Delta G}{n} = +35594J/molK\\\\b)\frac{\Delta G}{n} = -117711.7J/molK\\\\c) \frac{\Delta G}{n} = -94555.37J/molK\\\\b) \frac{\Delta G}{n} = -14472.75J/molK

With the results we can see that the reaction that would be most spontaneous is reaction b, as the Gibbs free energy is the most negative one. Also we see that reaction a occurs in the opposite direction.

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Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample
Dimas [21]

Answer:

<em>3.27·10²³ atoms of O</em>

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05\frac{g}{mol}.

We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.

19.3g <em>Na₂SO₄</em> · \frac{1 mol Na^2SO^4}{142.05g Na^2SO^4} · \frac{4 mol O}{1 mol Na^2SO^4} ·\frac{6.022x10^2^3}{1 mol O}

After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.

3 0
2 years ago
Bismuth(III) sulfate is an ionic compound formed from Bi3+ and SO42-. What is the correct way to represent the formula?
Hitman42 [59]

Answer:

Bi2(SO4)3

Explanation:

Bismuth(iii) sulfate is an ionic compound therefore, their is transfer of electron. Ionic compound has both cations and anions. The cations is positively charged ion while the anions is negatively charged ions. The cations loses electron to become positively charged while the anions gains electron to become negatively charged.

From the compound above, Bismuth(iii) sulfate the cations will be Bismuth ion which loses 3 electrons. The anions is the sulfate ion (S04)2- with a -2 charge.

The chemical formula can be computed from the charge configuration as follows

Bi3+  and (SO4)2-

cross multiply the charges living the sign behind to get the chemical formula

Bi2(SO4)3

Note the final chemical formula, the numbers are sub scripted

4 0
2 years ago
Acetonitrile (CH3CN) is a polar organic solvent that dissolves a wide range of solutes, including many salts. The density of a 1
erastovalidia [21]

Answer:

a. [LiBr] = 2.70 m

b. Xm for LiBr = 0.1

c. 81% by mass CH₃CN

Explanation:

Solvent → Acetonitrile (CH₃CN)

Solute → LiBr, lithium bromide

We convert the moles of solute to mass → 1.80 mol . 86.84 g/1 mol = 156.3 g

This mass of solute is contained in 1L of solution

1 L = 1000 mL → 1mL = 1cm³

We determine solution mass by density

Solution density = Solution mass / Solution volume

Solution density . Solution volume = solution mass

0.824 g/cm³ . 1000 cm³ = 824 g

Mass of solution = 824 g (solvent + solute)

Mass of solute = 156.3 g

Mass of solvent = 824 g - 156.3 g = 667.7 g

Molality → Moles of solute in 1kg of solvent

We convert the mass of solvent from g to kg → 667.7 g . 1kg /1000g = 0.667 kg

Mol/kg → 1.80 mol / 0.667 kg = 2.70 m → molality

Mole fraction → Mole of solute / Total moles (moles solute + moles solvent)

Moles of solvent → 667.7 g . 1mol/ 41g = 16.3 moles

Total moles = 16.3 + 1.8 = 18.1

Mole fraction Li Br → 1.80 moles / 18.1 moles = 0.1

Mass percentage → (Mass of solvent, <u>in this case</u> / Total mass) . 100

<u>We were asked for the acetonitrile</u> → (667.7 g / 824 g) . 100 = 81%

3 0
2 years ago
Dua buah gaya masing-masing F1 = 10 N dan F2 = 5 N bekerja pada sebuah benda yang:
Stolb23 [73]

Pertanyaan ini tidak ditulis dengan benar.

Pertanyaan Lengkap:

Duah buah gaya masing masing F1=10N dan F2=5N bekerja pada sebuah benda yang terletak pada suatu permukaan lantai. Jika benda berpindah ke kanan sejauh 5 meter,usaha yang dilakukan pada benda oleh kedua gaya tersebut adalah

Answer:

75 Nm or 75 Joules

Explanation:

Dari pertanyaan tersebut, kami telah diberikan parameter berikut:

F1 = 10N

F2 = 5N

D = 5 Meter.

Kita diminta untuk mencari atau menghitung usaha yang dilakukan pada benda oleh dua gaya.

Rumus kerja yang dilakukan pada suatu benda dengan dua gaya =

W = (F1 + F2) × D

Dimana D = Perpindahan benda

W = (10N + 5N) × 5m

W = 15N × 5m

W = 75Nm atau 75Joules

Oleh karena itu, usaha yang dilakukan pada benda tersebut dengan dua gaya = 75Nm atau 75 Joules

6 0
2 years ago
What mass of nickel (Ni) is in a 2.4 Kg sample of propanol if the concentration is 20 ppb ? (atomic mass of Ni = 58.69)
asambeis [7]

Answer:

The mass of nickel is 48μg

Explanation:

Parts per billion is a way to describe small concentrations and is defined as the ratio between μg of solute and kg of solvent.

If a solution of nickel in propanol is 20ppb, contains 20μg of nickel in 1 kg of propanol.

Thus, a sample of 2.4kg of propanol will contain:

2.4kg × (20μg nickel / 1kg) = 48μg nickel

<h3>The mass of nickel is 48μg</h3>
8 0
2 years ago
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