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ollegr [7]
1 year ago
15

Letícia leaves the grocery store and walks 150.0 m to the parking lot. Then, she turns 90° to the right and walks an additional

70.0 m to her car. What is the magnitude of the displacement of her car from the grocery store exit? Round your answer to the nearest tenth.
Physics
2 answers:
kvv77 [185]1 year ago
4 0
So you need to find the resulting length between the two distances. If you look at the two vectors as components of a right triangle then you can use Pythagorean theorem to solve for the last side. it is simply \sqrt{150^{2}+70^{2}}  which equals 165.5
Novosadov [1.4K]1 year ago
4 0

Answer:

165.5 m

Explanation:

In this problem, we have two displacements:

- A first displacement of 150.0 m forward

- A second displacement of 70.0 m to the right

The two displacement are in perpendicular direction, so in order to calculate the resultant displacement, we can use the Pytagorean theorem (in fact, the two displacements are the sides of a right triangle, and the hypothenuse corresponds to the magnitude of the resultant displacement).

Therefore, the magnitude of her total displacement is:

R=\sqrt{d_1 ^2 +d_2^2}=\sqrt{(150.0 m)^2+(70.0 m)^2}=165.5 m

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Two basketball teams are resting during halftime. While they are resting, a truck driver asks them for help pushing his broken d
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Answer:

It is a superordinate goal because both teams could have helped with the task.

Explanation:

If both teams pushed then they could have made it happened

7 0
2 years ago
In 1993, Ileana Salvador of Italy walked 3.0 km in under 12.0 min. Suppose that during 115 m of her walk Salvador is observed to
dexar [7]

Answer:

t = 25 seconds

Explanation:

Given that,

Distance, d = 115 m

Initial speed, u = 4.2 m/s

Final speed, v = 5 m/s

We need to find the time taken in increasing the speed.

We know that,

Acceleration, a=\dfrac{v-u}{t} ....(1)

The third equation of kinematics is as follows :

v^2-u^2=2ad\\\\\text{Put the value of a in above equation}\\\\v^2-u^2=2\times \dfrac{v-u}{t}\times d\\\\\because (a^2-b^2)=(a-b)(a+b)\\\\(v-u)(v+u)=\dfrac{2\times (v-u)d}{t}\\\\t=\dfrac{2d}{v+u}\\\\\text{Putting all the values}\\\\t=\dfrac{2\times 115}{4.2+5}\\\\t=25\ s

Hence, it will take 25 seconds to increase the speed.

6 0
1 year ago
A container of volume 0.6 m^3 contains 5.3 mol of argon gas at 24°C. Assuming argon behaves as an ideal gas, find the total inte
Vitek1552 [10]

Answer:

the internal energy of the gas is 433089.52 J

Explanation:

let n be the number of moles, R be the gas constant and T be the temperature in Kelvins.

the internal energy of an ideal gas is given by:

Ein = 3/2×n×R×T

     = 3/2×(5.3)×(8.31451)×(24 + 273)

     = 433089.52 J

Therefore, the internal energy of this gas is 433089.52 J.

5 0
1 year ago
Un cable está tendido sobre dos postes colocados con una separación de 10 m. A la mitad del cable se cuelga un letrero que provo
lisabon 2012 [21]

Answer:

El peso del cartel es 397,97 N

Explanation:

La tensión dada en cada segmento del cable = 2000 N

El desplazamiento vertical del cable = 50 cm = 0,5 m

La distancia entre los polos = 10 m

La posición del letrero en el cable = En el medio = 5

El ángulo de inclinación del cable a la vertical = tan⁻¹ (0.5 / 5) = 5.71 °

El peso del letrero = La suma del componente vertical de la tensión en cada lado del letrero

El peso del signo = 2000 × sin (5.71 grados) + 2000 × sin (5.71 grados) = 397.97 N

El peso del signo = 397,97 N.

8 0
2 years ago
A supersonic nozzle is also a convergent–divergent duct, which is fed by a large reservoir at the inlet to the nozzle. In the re
Lady_Fox [76]

Answer:

155.38424 K

2.2721 kg/m³

Explanation:

P_1 = Pressure at reservoir = 10 atm

T_1 = Temperature at reservoir = 300 K

P_2 = Pressure at exit = 1 atm

T_2 = Temperature at exit

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For isentropic flow

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The temperature of the flow at the exit is 155.38424 K

From the ideal equation density is given by

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The density of the flow at the exit is 2.2721 kg/m³

4 0
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