Question

The following questions will help you learn to apply the impulse-momentum theorem to the cases of constant and varying force acting along the direction of motion. First, let us consider a particle of mass m moving along the x axis. The net force F is acting on the particle along the x axis. F is a constant force. Part A The particle starts from rest at t=0. What is the magnitude p of the momentum of the particle at time t? Assume that t>0. Express your answer in terms of any or all of m, F, and t.

Answer 1

Answer:

$p=F\times t$

Explanation:

We are given:

• mass of the particle moving along x-axis = m

• force acting on paricle along x-axis = F

• time = t

momentum, p = ?

From the Newton's second law of motion:

$F=\frac{dp}{dt}$

where:

dp & dt are the change in momentum and change in time respectively.

Using the above eq. of the Newton's second law of motion:

$dp=F\times dt$

according to given:

$p=F\times t$

We also have for impulse:

$i=F\times t$