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alukav5142 [94]
2 years ago
10

Which of the following molecules would one expect to have a non-polar covalent bond?

Chemistry
1 answer:
Ivahew [28]2 years ago
7 0

b. F₂ have a polar covalent bond

Explanation:

The type of bond depends on the difference of the electronegativity of the two elements.

if the electronegativity difference is under 0.4 the bond is non-polar covalent

if the electronegativity difference is between 0.4 and 1.7 the bond is polar covalent

if the electronegativity difference is greater 1.7 the bond is ionic

a. HCl

electronegativity of Cl - electronegativity of H = 3 - 2.2 = 0.8, so the bond is polar covalent

b. F₂

electronegativity of F - electronegativity of F = 4 - 4 = 0 , so the bond is non-polar covalent

c. HF

electronegativity of F - electronegativity of H = 4 - 2.2 = 1.8, in this case because non-metals are involved in the bond we consider this to be a polar covalent bond.

d. ClF

electronegativity of F - electronegativity of Cl = 4 - 3 = 1, so the bond is polar covalent

Learn more about:

type of chemical bonds

brainly.com/question/13178368

brainly.com/question/2344549

#learnwithBrainly

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Drinking water may contain a low concentration of lead ion (Pb2 ) due to corrosion of old lead pipes. The EPA has determined tha
Lynna [10]

Answer:

3.861x10⁻⁹ mol Pb⁺²

Explanation:

We can <u>define ppm as mg of Pb²⁺ per liter of water</u>.

We<u> calculate the mass of lead ion in 100 mL of water</u>:

  • 100.0 mL ⇒ 100.0 / 1000 = 0.100 L
  • 0.100 L * 0.0080 ppm = 8x10⁻⁴ mg Pb⁺²

Now we <u>convert mass of lead to moles</u>, using its molar mass:

  • 8x10⁻⁴ mg ⇒ 8x10⁻⁴ / 1000 = 8x10⁻⁷ g
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4 0
2 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is
Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
2 years ago
Determine the velocity of a marble (m = 8.66 g) with a wavelength of 3.46 × 10-33m.a.45.2 m/sb.11.3 m/sc.22.1 m/sd.38.8 m/se.52.
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Answer:

Velocity = 22.11 m/s

Explanation:

Using the equation;

λ = h / mv;

where  

λ = wavelength ( 3.46 x 10^-33 )  

m = mass of the marble ( 8.66 g )  

v = velocity ( we gotta find out )  

h = planck's constant ( 6.626 * 10^-34 )  

Making v the subject of the formula;

V = h /mλ

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6 0
2 years ago
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Answer:

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Explanation:

We divide each mass by the element's relative atomic mass

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0.027-Ag, 0.0089-N

Divide by the lowest ratio

0.027/0.0089-Ag, 0.0089/0.0089 N

3-Ag, 1-N

Empirical formula- Ag3N

2)2.22/23-Na, 1.55/32-S

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Divide by the lowest ratio

0.097/0.048-Na, 0.048/0.048-S

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Empirical formula- Na2S

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Divide by the lowest ratio

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1-Na, 1-H, 1-S, 4-O

Empirical formula- NaHSO4

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0.047-K, 0.047-N, 0.14-O

Divide through by the lowest ratio

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1-K, 1-N, O-3

Empirical formula- KNO3

4 0
2 years ago
When magnesium ribbon is placed in sulfuric acid, a chemical reaction takes place and heat energy is given off. Liang and Naraba
kolezko [41]

Answer:

this is the answer

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6 0
2 years ago
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