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AlexFokin [52]
2 years ago
13

During a race such as a marathon, the skeletal muscle cells in your legs use a lot of energy to continually contract and power y

our muscles. What organelle is most likely abundant in skeletal muscle cells?
Physics
1 answer:
Komok [63]2 years ago
6 0

Answer:

The most likely abundant organelle in skeletal muscle cells are know as myofibrils which is a contractile apparatus mostly containing the contractile proteins actin and myosin with the regulatory proteins troponin and tropomyosin.

In addition the skeletal muscle cell cytoplasm contains numerous mitochondria, as well as abundant glycogen to provide energy. The contractile elements of skeletal muscle cells (myofibrils) are thin cylindrical structures 1–2 µm in diameter.

Explanation:

Skeletal muscle fibers, or muscle cells, are formed from the fusion of developmental myoblasts in a process known as myogenesis. Muscle fibers are cylindrical and have more than one nucleus. They also have multiple mitochondria to meet energy needs. Muscle fibers are in turn composed of myofibrils.

The myofibril is a long cylindrical organelle found in skeletal muscle cells formed by two transverse filament systems: the thick and thin filaments. The thin filament is composed primarily of actin; it is tethered at one end to the Z-disk, and it interdigitates with the thick filaments. Thaey slide past one another, producing a contraction that changes both the length and the shape of the cell to produce force and motion.

The skeletal muscle vigorous activity and unusually high energy requirement is powered by organelles known as mitochondria which resist the force of gravity, generate heat by shivering, pump blood, move substances through hollow organs and produce strong bodily movements.

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Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo
MrRa [10]

Explanation :

Takumi wears sunscreen and a hat each time he works in the yard. This is to protect himself with the strong radiation coming from the sun. UV rays that are coming from the sun are the main cause of skin cancer.

Stochastic effects are the effects that are caused by chance. Cancer is one of the main stochastic effects.

So, the correct option is (b) "the severity of stochastic effects, such as cancer".

7 0
3 years ago
Read 2 more answers
block of mass 0.5kg on a horizontal surface is attached to a horizontal spring of negligible mass and spring constant 50N/m . Th
Alisiya [41]

Answer:

Explanation:

The mass of the block is 0.5kg

m = 0.5kg.

The spring constant is 50N/m

k =50N/m.

When the spring is stretch to 0.3m

e=0.3m

The spring oscillates from -0.3 to 0.3m

Therefore, amplitude is A=0.3m

Magnitude of acceleration and the direction of the force

The angular frequency (ω) is given as

ω = √(k/m)

ω = √(50/0.5)

ω = √100

ω = 10rad/s

The acceleration of a SHM is given as

a = -ω²A

a = -10²×0.3

a = -30m/s²

Since we need the magnitude of the acceleration,

Then, a = 30m/s²

To know the direction of net force let apply newtons second law

ΣFnet = ma

Fnet = 0.5 × -30

Fnet = -15N

Fnet = -15•i N

The net force is directed to the negative direction of the x -axis

8 0
2 years ago
A single slit, which is 0.050 mm wide, is illuminated by light of 550 nm wavelength. What is the angular separation between the
likoan [24]

Answer:

The separation between the first two minima on either side is 0.63 degrees.

Explanation:

A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:

a\sin \theta_n=n\lambda

with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:

for the first minimum

a\sin \theta_1=(1)\lambda

solving for θ1:

\theta_1=\arcsin (\frac{\lambda}{a})=\arcsin (\frac{550\times10^{-9}}{0.05\times10^{-3}})

\theta_1=0.63 degrees

for the second minimum:

a\sin \theta_2=(2)\lambda

\theta_2=\arcsin (\frac{2\lambda}{a})=\arcsin (\frac{2*550\times10^{-9}}{0.05\times10^{-3}})

\theta_2=1.26 degrees

So, the angular separation between them is the rest:

\Delta \theta =1.26-0.63

\Delta \theta=0.63

4 0
2 years ago
Determine the values of m and n when the following mass of the Earth is written in scientific notation: 5,970,000,000,000,000,00
yuradex [85]

Explanation:

Mass of the Earth is equal to,

m=5,970,000,000,000,000,000,000,000\ kg

Any number can be written in the form of scientific notation as :

N=m\times 10^n

m is the real number

n is any integer

Mass of the earth can be written in the form of scientific notation as :

m=5.97\times 10^{24}\ m

Here,

m = 5.97

n = 24

Hence, this is the required solution.                                                      

7 0
2 years ago
A certain satellite travels in an approximately circular orbit of radius 2.0 × 106 m with a period of 7 h 11 min. Calculate the
kap26 [50]

Answer: Mass of the planet, M= 8.53 x 10^8kg

Explanation:

Given Radius = 2.0 x 106m

Period T = 7h 11m

Using the third law of kepler's equation which states that the square of the orbital period of any planet is proportional to the cube of the semi-major axis of its orbit.

This is represented by the equation

T^2 = ( 4π^2/GM) R^3

Where T is the period in seconds

T = (7h x 60m + 11m)(60 sec)

= 25860 sec

G represents the gravitational constant

= 6.6 x 10^-11 N.m^2/kg^2 and M is the mass of the planet

Making M the subject of the formula,

M = (4π^2/G)*R^3/T^2

M = (4π^2/ 6.6 x10^-11)*(2×106m)^3(25860s)^2

Therefore Mass of the planet, M= 8.53 x 10^8kg

5 0
2 years ago
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