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2 years ago

3

A hollow pipe is submerged in a stream of water so that the length of the pipe is parallel to the velocity of the water. If the

water speed doubles and the cross-sectional area of the pipe triples, what happens to the volume flow rate of the water passing through the pipe?
A) The volume flow rate does not change.
B)The volume flow rate increases by a factor of 2.
C)The volume flow rate increases by a factor of 3.
D)The volume flow rate increases by a factor of 6.

2 answers:

slavikrds [6]2 years ago

6 0

D. The volume flow rate increases by a factor of six

Basile [38]2 years ago

5 0

Answer:

D)The volume flow rate increases by a factor of 6

Explanation:

Volume = Area * Velocity

Velocity is doubled V = 2

Area is tripled A = 3

Volume 3 * 2 = 6m^3/s

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For the sphere on the left hand side, moment of inertia I

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Then we obtain

$v=\sqrt {\frac {gL^{3}(m2-m1)}{4(\frac {L^{2}(M+3m1+3m2)}{12})}}=\sqrt {\frac {3gL^{3}(m2-m1)}{L^{2}(M+3m1+3m2)}}$

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Oduvanchick [21]

Answer:

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$E_2=\dfrac{kq_2}{r^2}$

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