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Alik [6]
2 years ago
7

The gold foil experiment led to the conclusion that each atom in the foil was composed mostly of empty space because most alpha

particles directed at the foil
(1) passed through the foil
(2) remained trapped in the foil
(3) were deflected by the nuclei in gold atoms
(4) were deflected by the electrons in gold atoms

Physics
2 answers:
Sholpan [36]2 years ago
6 0

Answer:

Option 1

Explanation:

The correct answer is option 1

The gold foil experiment was conducted by Rutherford. This experiment was conducted to study the Atom.

In the experiment Alpha rays from the emitter are passed through gold foil and there was a receiver that was present there to intercept the alpha rays.

The outcome of the result was that most of the alpha particle pass through foil undeflected and very few rays revert back on the original path from the heavy mass present at the center.

Later this heavy mass was known Nucleus.

Hence, most alpha particles passed through the foil.

katovenus [111]2 years ago
5 0

Answer:

(1) passed through the foil

Explanation:

Ernest Rutherford conducted an experiment using an alpha particle emitter projected towards a gold foil and the gold foil was surrounded by a fluorescent screen which glows upon being struck by an alpha particle.

  • When the experiment was conducted he found that most of the alpha particles went away without any deflection (due to the empty space) glowing the fluorescent screen right at the point of from where they were emitted.
  • While a few were deflected at reflex angle because they were directed towards the center of the nucleus having the net effective charge as positive.
  • And some were acutely deflected due to the field effect of the positive charge of the proton inside the nucleus. All these  conclusions were made based upon the spot of glow on the fluorescent screen.

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A world class runner can run long distances at a pace of 15 km/hour. That runner expends 800 kilocalories of energy per hour. a)
Talja [164]
<h2>Answer:</h2>

(a) 933.33W

(b) 3.36 x 10⁶J

<h2>Explanation:</h2>

(a) Power is the time rate of change of energy.

In the question, the runner expends 800 kilocalories (kcal) of energy in one hour (h).

That means that power expended is 800 kcal / h.

To get the power in Watts, we convert 800 kcal/h to Joules per second (J/s) as follows;

(i) First convert kcal to Joules (J)

1 cal = 4.2 J

1 kcal = 1 x 1000 cal = 1 x 1000 cal x 4.2 J / 1 cal = 4200 J

(ii) Then convert 1 hour to second (s)

1 h = 3600s

(iii) Now convert 800 kcal/h to J/s

800 kcal / h = \frac{800 * 1 k cal}{1 h} = \frac{800 * 4200J}{3600s} = 933.33J/s = 933.33W

Therefore, the power expended in J/s (or in Watts) is 933.33

(b) According to the question, the runner can run 15km in 1 hour and will expend a power of 933.33W. To calculate the energy expended at this time, we use the formula;

E = P x t             -------------------(ii)

Where;

E = Energy

P = Power = 933.33W

t = time taken = 1 hour = 36000s

Substitute these values into equation (ii) as follows;

E = 933.33 x 3600

E = 3359988 J

E = 3.36 x 10⁶ J

Therefore, the total energy is 3.36 x 10⁶J

7 0
2 years ago
Feng and Isaac are riding on a merry-ground. Feng rides on a horse at the outer rim of the circular platform, twice as far from
kogti [31]

Answer: The question is incomplete or missing details. here is the remaining part of the question ;

1. impossible to determine

2. half of Isaac’s

3. the same as Isaac’s

4. twice Isaac’s

The angular speed of feng will be the same as that of Isaac. Hence the answer is option 3

Explanation:

Since we have been told that both feng and isaac are riding on a merry go round i.e in a circular motion, irrespective of how fast one ride above the other, the angular speed will be constant since they are riding on a merry go round, as such both feng and isaac will maintain equal angular speed, hence the angular speed of feng will be the same as that of Isaac.

4 0
2 years ago
A 1.0-kg ball has a velocity of 12 m/s downward just before it strikes the ground and bounces up with a velocity of 12 m/s upwar
Nezavi [6.7K]

Answer:

The change in momentum of the ball is 24 kg-m/s  

Explanation:

It is given that,

Mass of the ball, m = 1 kg

Initial velocity of the ball, u = -12 m/s (in downwards)

Final velocity of the ball, v = +12 m/s (in upward)

We need to find the change in momentum of the ball.

Initial momentum of the ball, p_i=mu=1\ kg\times (-12\ m/s)=-12\ kg-m/s

Final momentum of the ball, p_f=mv=1\ kg\times (12\ m/s)=12\ kg-m/s

Change in momentum of the ball, \Delta p=p_f-p_i

\Delta p=12-(-12)=24\ kg-m/s

So, the change in momentum of the ball is 24 kg-m/s. Hence, this is the required solution.

3 0
2 years ago
A man stands on his balcony, 130 feet above the ground. He looks at the ground, with his sight line forming an angle of 70° with
jenyasd209 [6]

Answer:

d =  380 feet

Explanation:

Height of man = perpendicular= 130 feet

Angle of depression = ∅ = 70 °

distance to bus stop from man = hypotenuse = d = 130 sec∅

As sec ∅ = 1 / cos∅

so d = 130 sec∅    or d = 130 / cos∅

d = 130 / cos(70°)

d =  380 feet

8 0
2 years ago
You are using a lightweight rope to pull a sled along level ground. The sled weighs 485 N, the coefficient of kinetic friction b
Bogdan [553]

Answer:

N=459.01N

Explanation:

According to Newton's first law:

N+F_y-W=0

The component of the force on the y-axis can be obtained through the Pythagorean Theorem. This is because the components are the cathetus of a right triangle and its hypotenuse is the magnitude of the force:

sin12^\circ=\frac{F_y}{F}\\F_y=Fsin12^\circ

Replacing and solving for N:

N=W-Fsin12^\circ\\N=485N-(125N)sin12^\circ\\N=459.01N

5 0
2 years ago
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